Answer:
1. x = 2, AC = 30, AB - 4
2. y = 4, AB = 34, BC = 34
Step-by-step explanation:
1. AB + BC = AC so 26 + (10 - 3x) = 14x +2 and then add 3x to both sides and subtract 2 from both sides to get x on one side and an integer on the other side which is 34 = 17x and then divide 17 from both sides to get x = 2 and then substitute x into the AC and AB equations to find the values its equal to.
2. The symbol in the given means that the two lengths are congruent which means they are equal to each other so you put the two equations equal to each other and solve for y. 9y -2 = 14 + 5y, so subtract 5y from both sides and add two to both sides to get 4y = 16 and then divide both sides by 4 to get y = 4 and then substitute in the answer to find the lengths of AB and BC.
2x-4(x+1)=-13
1) we solve this equation:
2x-4(x+1)=-12
2x-4x-4=-12
-2x=-12+4
-2x=-8
x=-8/-2
x=4
2) we evalute x²-1
x²-1=4²-1=16-1=15
Answer: 15
To solve this problem, we must use the order of operations outlined by PEMDAS, which tells us that we should simplify or compute parentheses first, then exponents, multiplication, division, addition, and finally subtraction.
Using this method, we have to perform the multiplication inside the parentheses first.
(20 * 40) * 14
800 * 14
Finally, we must perform the final operation to simplify this expression, which is multiplication.
800 * 14 = 11200
Therefore, your final answer is 11200.
Hope this helps!
Answer:
a=55
b=55
c=125
d=125
e=55
f=55
g=125
Step-by-step explanation:
Answer:
1 / 2
Step-by-step explanation:
- First observe that the fate of the last person is determined the moment either the first or the last seat is selected! This is because the last person will either get the first seat or the last seat. Any other seat will necessarily be taken by the time the last guy gets to 'choose'.
- Since at each choice step, the first or last is equally probable to be taken, the last person will get either the first or last with equal probability: 1/2
- Armed with the key observation, we see that the event that the last person's correct seat is free, is exactly the same as the event that the first person's seat was taken before the last person's seat.
- Well, each person had to make a random choice, was equally likely to choose the first person's seat or the last person's seat - the random chooser exhibits absolutely no preference towards a particular seat. This means that the probability that one seat is taken before the other must be 1/2
