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PIT_PIT [208]
3 years ago
7

The base of this regular right pyramid is a square. What is its surface area?

Mathematics
1 answer:
natta225 [31]3 years ago
4 0

Answer:

○ C) 256 in.²

Step-by-step explanation:

{a}^{2} + 2a \sqrt{ \frac{ {a}^{2}}{4} + {h}^{2} } = S. A. \\ \\ {8}^{2} + 2(8) \sqrt{ \frac{{8}^{2}}{4} + {12}^{2}} = 64 + 64\sqrt{10}\\ \\ 64\sqrt{10} ≈ 266,3857703 ≈ 256

I am joyous to assist you anytime.

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The midpoints are (8,3) and (6.5,6).

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Midpoint formula = ((x1+x2)/2 , (y1+y2)/2)

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3 years ago
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