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PIT_PIT [208]
3 years ago
7

The base of this regular right pyramid is a square. What is its surface area?

Mathematics
1 answer:
natta225 [31]3 years ago
4 0

Answer:

○ C) 256 in.²

Step-by-step explanation:

{a}^{2} + 2a \sqrt{ \frac{ {a}^{2}}{4} + {h}^{2} } = S. A. \\ \\ {8}^{2} + 2(8) \sqrt{ \frac{{8}^{2}}{4} + {12}^{2}} = 64 + 64\sqrt{10}\\ \\ 64\sqrt{10} ≈ 266,3857703 ≈ 256

I am joyous to assist you anytime.

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PLEASE RIGHT ANSWERS ONLY!!
Temka [501]

Answer

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Step-by-step explanation:

algebra ll

4 0
2 years ago
What is the center of the circle whose diameter has endpoints (18, -13) and (4, -3)?
jeka94

Answer:

Step-by-step explanation:

The center of the circle whose diameter has endpoints (18, -13) and (4, -3) will be the midpoint of the coordinates.

The ormua for calculating mid point is expressed as;

M(X,Y) ={(x21+x2/2, y1+y2/2}

X= x1+x2/2

Y = y1+y2/2

From the coordinates

x1 = 18 x2 = 4

X= 18+4/2

X = 22/2

X = 11

y1= -13, y2= -3

Y = -3-13/2

Y = -16/2

Y = -8

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4 0
3 years ago
Read 2 more answers
Calculate the sum of the multiples of 4 from 0 to 1000
allochka39001 [22]

Answer:

sum is 125,500

sum in summation notation is \sum\limits_{n=0}^n a+nd= (2a+(n-1)d)n/2

Step-by-step explanation:

This problem can be solved using concept of arithmetic progression.

The sum of n term terms in arithmetic progression is given by

sum = (2a+(n-1)d)n/2

where

a is the first term

d is the common difference of arithmetic progression

_____________________________________________________

in the problem

series is multiple of 4 starting from 4 ending at 1000

so series will look like

series: 0,4,8,12,16..................1000

a is first term so

here a is 0

lets find d the common difference

common difference is given by nth term - (n-1)th term

lets take nth term as 8

so (n-1)th term = 4

Thus,

d = 8-4 = 4

d  can also be seen 4 intuitively as series is multiple of four.

_____________________________________________

let calculate value of n

we have last term as 1000

Nth term can be described

Nth term = 0+(n-1)d

1000 =   (n-1)4

=> 1000 = 4n -4

=> 1000 + 4= 4n

=> n = 1004/4 = 251

_____________________________________

now we have

n = 1000

a = 0

d = 4

so we can calculate sum of the series by using formula given above

sum = (2a+(n-1)d)n/2

       = (2*0 + (251-1)4)251/2

       = (250*4)251/2

     = 1000*251/2 = 500*251 = 125,500

Thus, sum is 125,500

sum in summation notation is \sum\limits_{n=0}^n a+nd= (2a+(n-1)d)n/2

3 0
2 years ago
How do I <br> Divide. Write in simplest form
sladkih [1.3K]

Answer:

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Step-by-step explanation:

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3 years ago
A camera has a list price of $579.99 before tax. If the sales tax rate is 7.25%, find the total cost of the camera with sales ta
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Answer:

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519.99 + 42.899 = $562.89

Step-by-step explanation:

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2 years ago
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