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3 years ago

The base of this regular right pyramid is a square. What is its surface area?

Mathematics

1 answer:

natta225 [31]3 years ago

4 0

Answer:

○ C) 256 in.²

Step-by-step explanation:

{a}^{2} + 2a \sqrt{ \frac{ {a}^{2}}{4} + {h}^{2} } = S. A. \\ \\ {8}^{2} + 2(8) \sqrt{ \frac{{8}^{2}}{4} + {12}^{2}} = 64 + 64\sqrt{10}\\ \\ 64\sqrt{10} ≈ 266,3857703 ≈ 256

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Step-by-step explanation:

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*Use a <em>t</em>-table for the critical value.

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