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PIT_PIT [208]
3 years ago
7

The base of this regular right pyramid is a square. What is its surface area?

Mathematics
1 answer:
natta225 [31]3 years ago
4 0

Answer:

○ C) 256 in.²

Step-by-step explanation:

{a}^{2} + 2a \sqrt{ \frac{ {a}^{2}}{4} + {h}^{2} } = S. A. \\ \\ {8}^{2} + 2(8) \sqrt{ \frac{{8}^{2}}{4} + {12}^{2}} = 64 + 64\sqrt{10}\\ \\ 64\sqrt{10} ≈ 266,3857703 ≈ 256

I am joyous to assist you anytime.

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Find the surface area of each figure. Round your answers to the nearest hundredth, if necessary
algol13

Answer

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Step-by-step explanation:

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4 0
3 years ago
What is the error of the problem? I don't quite understand but I'll like if anyone can explain it to me :)))
egoroff_w [7]

Answer:

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Step-by-step explanation:

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3 years ago
A rectangular prism has a length of 7 cm, a width of 4 cm, and a height of 2
Scilla [17]

Answer:

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Step-by-step explanation:

It is given that,

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Therefore the correct answer is 448 cubes

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Reptile [31]

Answer and Explanation:

Given : The random variable x has the following probability distribution.

To find :

a. Is this probability distribution valid? Explain and list the requirements for a valid probability distribution.

b. Calculate the expected value of x.

c. Calculate the variance of x.

d. Calculate the standard deviation of x.

Solution :

First we create the table as per requirements,

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0    0.25           0               0                0

1     0.20        0.20             1              0.20

2    0.15          0.3               4             0.6

3    0.30         0.9               9             2.7

4    0.10          0.4               16             1.6

   ∑P(x)=1     ∑xP(x)=1.8               ∑x²P(x)=5.1

a) To determine that table shows a probability distribution we add up all five probabilities if the sum is 1 then it is a valid distribution.

\sum P(X)=0.25+0.20+0.15+0.30+0.10

\sum P(X)=1

Yes it is a probability distribution.

b) The expected value of x is defined as

E(x)=\sum xP(x)=1.8

c) The variance of x is defined as

V=\sum x^2P(x)-(\sum xP(x))^2\\V=5.1-(1.8)^2\\V=5.1-3.24\\V=1.86

d) The standard deviation of x is  defined as

\sigma=\sqrt{V}

\sigma=\sqrt{1.86}

\sigma=1.136

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3 years ago
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