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2 years ago

Please help! Greatly appreciated sorry for really bad quality

Mathematics

1 answer:

Degger [83]2 years ago

7 0

The first answer.

Point P is at (50,-40) the distance from Q to P is 80 units which you can find by subtracting the x of Q (-30) from the x of P (50).
50-(-30)=80
It then tells you point R is vertically above point Q so you know your x value for R will be the same as Q.
Add your distance from Q to P of 80 units to the y value of Q because you are traveling up.
-40+80=40
R will have a point of (-30,40) and a distance of 80 units

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Any volunteer please help

den301095 [7]

Answer:

Part A)

The equation in the point-slope form is:

$y-11=\frac{4}{3}\left(x-\left(-2\right)\right)$

Part B)

The graph of the equation is attached below.

Step-by-step explanation:

Part A)

Given

The point = (-2, 11)

m = 4/3

The point-slope form of the line equation is

$y-y_1=m\left(x-x_1\right)$

Here, m is the slope and (x₁, y₁) is the point

substituting the values m = 4/3 and the point (-2, 11) in the point-slope form of the line equation

$y-y_1=m\left(x-x_1\right)$

$y-11=\frac{4}{3}\left(x-\left(-2\right)\right)$

Thus, the equation in the point-slope form is:

$y-11=\frac{4}{3}\left(x-\left(-2\right)\right)$

Part B)

As we have determined the point-slope form which passes through the point (-2, 11) and has a slope m = 4/3

The graph of the equation is attached below.

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2 years ago

Steve drove at a constant rate to the beach for a vacation. In the equation below, t is the time in hours it took Steve to drive

My name is Ann [436]

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3 years ago

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A girl 1.54m girl, is 30m away from tower whose height is 53.5m. determine the angel of angle of elevation from her eye to the t

steposvetlana [31]

Answer:

reference attached

Step-by-step explanation:

<h2>hope it helps you<3</h2>

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2 years ago

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Fifty-five percent of the members of the junior varsity swim team wear glasses. Of the team memebers who do not wear glasses, 30

GarryVolchara [31]

the probability that a randomly chosen member of the JV swim team does not wear glasses and is in the 10th grade is 14%.

Given, the members of the junior varsity swim team wear glasses is 55%.

And the members of junior varsity swim team who do not wear glasses and in 10th grade is 30%.

Let the total no. of members be x.

So, the members of the junior varsity swim team wear glasses (55%),will be

$0.55x$ .

The total number of members not wearing glasses, will be

$x - 0.55 x = 0.45 x$ .

Now, the no. of members not wearing glasses and in 10th grade will be,

$\frac{0.45x\times30}{100} =0.135x$

We know that the probability of an event E, P(E) will be,

$P(E)=\frac{No.\ of Favourable\ outcomes}{total \ no. \ of \ outcomes}$

So, the probability for no. of members not wearing glasses and in 10th grade will be,

$P(E)=\dfrac{0.135x}{x}$

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For more details on probability follow the link:

brainly.com/question/795909

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