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agasfer [191]
4 years ago
11

How do you write the equation for a graph?

Mathematics
1 answer:
ZanzabumX [31]4 years ago
6 0
To write an equation in slope-intercept form, given a graph of that equation, pick two points on the line and use them to find the slope. This is the value of m in the equation. Next, find the coordinates of the y -intercept--this should be of the form (0, b)
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Sarah Beth babysits and earns $10.50 per hour which of the following best represents the relationship between the number of hour
Romashka [77]

Answer:

Step-by-step explanation:

didnt give all the info

7 0
3 years ago
(ii) The probability the tiles are both the same colour is 16 45 Show that x2 - 6x + 5 = 0.<br>​
nika2105 [10]

Answer:

i think probably x = 1 or 5

Step-by-step explanation:

x²-6x+5 =0

so (x-1)(x-5) = 0

so x = 1 or 5

6 0
2 years ago
PLEASE HELP ASAP!!!!!!!!!!!!!
Alchen [17]

Answer:

3 + 8 times 3 +27 times 3 + 64 times 3+ 125 times 3  + 216 times 3+ 343 times 3

2352 cubic units^3

Step-by-step explanation:

3 0
3 years ago
Is it possible for eight employees to earn between $300 and $350 while the ninth earns $1250 per week, and the mean to be $430?
Deffense [45]
According to Google, yes.... any details, I have no idea, but I hope I helped in any way, haha
Good luck~~
4 0
3 years ago
Conservationists tagged 120 ​black-nosed rabbits in a national forest in 1990. In 1991​, they tagged 240 ​black-nosed rabbits in
Sauron [17]

Answer:

Hence after period of 9 years from 1990 t0 1999 will be 61438 rabbits.

Step-by-step explanation:

Given:

Population for rabbit obeys exponential law.

120 at 1990 and 240 1991 ...after 1 year time period

To Find:

After 9 year  time period how many rabbits will be there.

Solution:

Exponential law goes on present value and various value and time period and defined as ,

let Y be present value Y0 previous year value  and k exponential constant and t be time period.

So

Y=Y0e^(kt)

Here Y=240  ,Y0=120  t=1 year time period

So

240=120e^(k*1)

240/120=e^k

2=e^k

Now taking log on both side, [natural log]

ln(2)=ln(e^k)

ln(2)=kln(e)

k=ln(2)

k=0.6931

For t=9 year of time period

Y0=120,  t=9  ,k=0.6931

Y=Y0e^(k*t)

Y=120*e^(0.6931*9)

=120e^6.2383

=61438.48

=61438 rabbits

8 0
4 years ago
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