Equation: M1V1 = M2V2
Where M = concentration & V = volume
Step 1: Write down what is given and what you are trying to find
Given: M1 = 1.25M, V1 = 46mL, and V2 = 250mL
Find: M2
Step 2: Plug in the values into the equation
M1V1 = M2V2
(1.25M)(46mL) = (M2)(250mL)
Step 3: Isolate the variable (Divide both sides by 250mL so M2 is by itself)
(1.25M)(46mL) / (250mL) = M2
Answer: M2 = 0.23M
Answer:
- <u><em>9.01 g of fertilizer</em></u>
Explanation:
Assume initially that the amount in grams of the multinutrient fertilizer is 100 g, and calculate the amount of nitrogen supplied by every compound present in these 100 g of fertilizer.
<u>1) Urea (CH₄N₂O)</u>:
- Molar mass of urea: 60.06 g/mol
- Atomic mass of N: 14.007 g/mol
- Total mass of N in the formula: 2 × 14.007 g/mol = 28.014 g/mol
- Amount of N in 100 g of compound: 100 g × 54.8% × 28.014 g / 60.06 g = 25.56 g
<u>2) KNO₃</u>
- Molar mass of KNO₃: 101.1032 g/mol
- Atomic mass of N: 14.007 g/ mol
- Total mass of N in the formula: 14.007 g/mol
- Amount of N in 100 of the compound: 100 g × 26.3% × 14.007 / 101.1032 = 3.64 g
<u>3) (NH₄)₂PO₄</u>
- Molar mass of (NH₄)₂PO₄: 132.06 g/mol
- Atomic mass of N: 14.007 g/ mol
- Total mass of N in the formula: 2×14.007 g/mol = 28.014 g/mol
- Amount of N in 100 of the compound: 100 g × 14.1% × 14.007 / 132.06 = 2.99 g
4) <u>Total mass of N in 100 g of fertilizer</u>:
Add all the amounts of N obtained above
- 25.56g + 3.69 g + 2.99 g = 32.19 g of N
5) <u>Mass of fertilizer that should be applied to provide 2.90 g of N to a plant</u>.
Set a proportion:
- 32.19 g of N / 100 g of fertilizer = 2.90 g of N / X
Solve for X:
- X = 2.90 g of N × 100 g of fertilizer / 32.19 g of N = 9.01 g of fertilizer
That is the answer: 9.01 g of fertilizer should be applied to provide 2.90g of N to a plant.
Answer:
283 grams KCl
Explanation:
To convert form moles to grams, you need to find the molar mass of your compound. The molar mass can be calculated using the individual molar masses of each element in the compound. These values can be found on the periodic table.
Molar Mass (K) = 39.098 g/mol
Molar Mass (Cl) = 35.453 g/mol
Molar Mass (KCl) = 39.098 g/mol + 35.453 g/mol
Molar Mass (KCl) = 74.551 g/mol
Now that you know the molar mass, you want to multiply it by the moles of KCl. This is possible because the molar mass is actually a ratio representing the relationship of grams and moles. In KCl, there are 74.551 grams of KCl for every 1 mole of KCl. When you are multiplying, make sure you set the ratio up in a way that allows for the units to cancel out and leave grams as your final answer.
3.80 moles KCl 74.551 g
----------------------- x ------------------- = 283 grams KCl
1 mole KCl
The final answer should have 3 sig figs because the value the problem gave (3.80 mol) also has 3 sig figs.
The answer is B as isotopes are different versions of the same chemical element containing the same amount of protons and electrons but different amounts of neutrons.
