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3 years ago

Sedimentary plus something that can equal metamorphic

Chemistry

1 answer:

Katena32 [7]3 years ago

3 0

Answer:

limestone+heat=marble

sandstone+heat=metaquartzite

shale+heat=quartzite

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Can geothermal energy be used for electricity

saw5 [17]

Yea but its not used very often

3 0

4 years ago

A metal is found that has a mass of 27g and will displace 6mL of water. Calculate its density and identify the metal.

melisa1 [442]

The density of metal = 4.5 g/ml, and the metal = Titanium

<h3>Further explanation </h3>

Density is a quantity derived from the mass and volume

Density is the ratio of mass per unit volume

Density formula:

$\large {\boxed {\bold {\rho ~ = ~ \frac {m} {V}}}}$

ρ = density

m = mass

v = volume

mass of metal=27 g

volume = 6 ml

The density :

$\tt \rho=\dfrac{27}{6}\\\\\rho=4.5~g/ml$

The metal with a density of 4.5 g/ml is Titanium

3 0

3 years ago

What are metalloids

dem82 [27]

A metalloid is an element that has properties that are intermediate between those of metals and nonmetals. Metalloids can also be called semimetals. On the periodic table, the elements colored yellow, which generally border the stair-step line, are considered to be metalloids.

7 0

3 years ago

What is the pOH of a<br> 2.6 x 10-6 M H+ solution?

melomori [17]

Answer:

Approximately $8.41$ (assuming that the solution is at $\rm 25^\circ C$ , under which $K_{\rm w} = 10^{-14}$ .)

Explanation:

Let ${\rm [H^{+}]}$ and ${\rm [OH^{-}]}$ denote the concentration of $\rm H^{+}$ and $\rm OH^{-}$ respectively.

Let $K_{\rm w}$ denote the self-ionization constant of water. The exact value of $K_{\rm w}\!$ depends on the temperature of the solution. $K_{\rm w} =10^{-14}$ at $\rm 25^\circ C$ .

The product of ${\rm [H^{+}]}$ and ${\rm [OH^{-}]}$ in a solution (with $\rm M$ , or moles per liter, as the unit) is supposed to be equal to the $K_{\rm w}$ value of that solution at the corresponding temperature. In other words:

${\rm [H^{+}]} \cdot {\rm [OH^{-}]} = K_{\rm w}$ .

Rearrange to obtain an expression for ${[\rm OH^{-}]}$ :

$\begin{aligned}{\rm [OH^{-}]} &= \frac{K_{\rm w}}{[\rm H^{+}]}\end{aligned}$ .

Assume that the solution in this question is at $\rm 25^\circ C$ (for which $K_{\rm w} =10^{-14}$ .) For this solution:

$\begin{aligned}{\rm [OH^{-}]} &= \frac{K_{\rm w}}{[\rm H^{+}]} \\ &= \frac{10^{-14}}{2.6 \times 10^{-6}}\approx 3.85\times 10^{-9}\; \rm M\end{aligned}$ .

Hence, the $\rm pOH$ of this solution would be:

$\begin{aligned}\rm pOH &= -\log_{10}{\rm [OH^{-}]} \\&\approx -\log_{10} (3.85 \times 10^{-9}) \approx 8.41 \end{aligned}$ .

3 0

3 years ago

Name the phase change in each of these events: (c) Wet clothes dry on a summer day

8090 [49]

The phase change occurs during evaporation. On a hot day, wet clothing is drying. A liquid becomes a gas when it evaporations.

During the process of evaporation, a liquid transforms into a gaseous phase that is not saturated with the evaporating substance. The term "vaporization of a liquid" refers to this process. Clothes start to dry as water vapor escapes from the fabric's surface.

<h3>What is evaporation?</h3>

A liquid turns into a gas through the process of evaporation. Raindrops that "vanish" on a hot day or damp clothing that dries in the sun are good examples of the phenomena. In these instances, the liquid water is evaporating into a gas known as water vapor rather than really dissipating. Global evaporation takes place.

Learn more about evaporation: brainly.com/question/5019199

#SPJ4

5 0

2 years ago