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Pachacha [2.7K]
3 years ago
13

If i start with 46 ml of 1.25 m hcl and dilute it to a volume of 250 ml, what is the concentration of my final solution

Chemistry
1 answer:
ikadub [295]3 years ago
7 0
Equation: M1V1 = M2V2

Where M = concentration & V = volume

Step 1: Write down what is given and what you are trying to find

Given: M1 = 1.25M, V1 = 46mL, and V2 = 250mL
Find: M2

Step 2: Plug in the values into the equation

M1V1 = M2V2
(1.25M)(46mL) = (M2)(250mL)

Step 3: Isolate the variable (Divide both sides by 250mL so M2 is by itself)

(1.25M)(46mL) / (250mL) = M2

Answer: M2 = 0.23M 
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Liquid hexane
maks197457 [2]

<u>Answer:</u> The mass of H_2O produced is 2.52 g

<u>Explanation:</u>

The number of moles is defined as the ratio of the mass of a substance to its molar mass.  The equation used is:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}} ......(1)

  • <u>For hexane:</u>

Given mass of hexane = 1.72 g

Molar mass of hexane = 86.18 g/mol

Putting values in equation 1, we get:

\text{Moles of hexane}=\frac{1.72g}{86.18g/mol}=0.020mol

  • <u>For oxygen gas:</u>

Given mass of oxygen gas = 8.0 g

Molar mass of oxygen gas= 32 g/mol

Putting values in equation 1, we get:

\text{Moles of water}=\frac{8.0g}{32g/mol}=0.25mol

The chemical equation for the combustion of hexane follows:

2C_6H_{14}+19O_2\rightarrow 12CO_2+14H_2O

By stoichiometry of the reaction:

If 2 moles of hexane reacts with 19 moles of oxygen gas

So, 0.020 moles of hexane will react with = \frac{19}{2}\times 0.020=0.19mol of oxygen gas

As the given amount of oxygen gas is more than the required amount. Thus, it is present in excess and is considered as an excess reagent.

Thus, hexane is considered a limiting reagent because it limits the formation of the product.

By the stoichiometry of the reaction:

If 2 moles of hexane produces 14 moles of H_2O

So, 0.020 moles of hexane will produce = \frac{14}{2}\times 0.020=0.14mol of H_2O

We know, molar mass of H_2O = 18 g/mol

Putting values in above equation, we get:

\text{Mass of }H_2O=(0.14mol\times 18g/mol)=2.52g

Hence, the mass of H_2O produced is 2.52 g

4 0
3 years ago
How many moles of sodium cyanide (NaCN) would be needed to produce 4.2 moles of sodium sulfate (Na2SO4)? H2SO4 + 2NaCN → 2HCN +
leonid [27]
The purpose of a chemical equation is to relate the amounts of reactants to the amounts of products based on the rate each is consumed. In this problem, one mole of sulfuric acid is consumed along with two moles of sodium cyanide to produce two moles of hydrocyanic acid and one mole of sodium sulfate. The relationship between sodium cyanide and sodium sulfate is 2:1, meaning that two moles of NaCN is required to produce one mole of sodium sulfate.

To produce 4.2 moles of sodium sulfate, two times this amount of NaCN is required. This means that you would need 8.4 moles of sodium cyanide.

Hope this helps!
4 0
3 years ago
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When sulfur burns, it forms sulfur dioxide (SO2). Its chemical reaction is S + O2 → SO2.
Elenna [48]

Answer:

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Explanation:

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In this case, the reactants Sulfur (S) and Oxygen (O2) must equal the mass of the product Sulfur Dioxide (SO2). Therefore, the statement <em>"The mass of SO2 will be equal to the sum of the mass of S and O2" </em>is correct.

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I know the answer. It is 2 straight chains. lLOL
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Can A fire extinguisher kill A Human Being
skad [1K]
Yes. it could kill someone because they are designed to take the oxygen out of the atmosphere to put out a fire, You can kill a person by suffixation, You can purchase a unit that gives off a harmless vapor that resembles white smoke though.
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2 years ago
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