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3 years ago

If i start with 46 ml of 1.25 m hcl and dilute it to a volume of 250 ml, what is the concentration of my final solution

1 answer:

7 0

Equation: M1V1 = M2V2

Where M = concentration & V = volume

Step 1: Write down what is given and what you are trying to find

Given: M1 = 1.25M, V1 = 46mL, and V2 = 250mL
Find: M2

Step 2: Plug in the values into the equation

M1V1 = M2V2
(1.25M)(46mL) = (M2)(250mL)

Step 3: Isolate the variable (Divide both sides by 250mL so M2 is by itself)

(1.25M)(46mL) / (250mL) = M2

Answer: M2 = 0.23M

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We need 42.4 mL of benzene to produce 1.5 *10³ kJ of heat

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Step 1: Data given

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Step 2: The balanced equation

2 C6H6(l) + 15 O2(g) → 12 CO2(g) + 6 H2O(g) ΔH°rxn = -6278 kJ

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Step 4: Calculate mass of benzene

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Step 5: Calculate volume of benzene

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Explanation:

The reactions that take place in the electric furnace method are:

1) P₄ + 5O₂ → P₄O₁₀

This is a redox reaction, because the oxidation state of the reactants is changed.

2) P₄O₁₀ + 6H₂O → 4H₃PO₄

This is an acid-base reaction, because there's an exchange of H⁺ species.

The reaction that takes place in the wet process is:

3) Ca₅(PO₄)₃F + 5H₂SO₄ → 3H₃PO₄ + HF + 5CaSO₄

This is an precipitation reaction, because a precipitate (a solid phase in a liquid phase) is formed.

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