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Pachacha [2.7K]
3 years ago
13

If i start with 46 ml of 1.25 m hcl and dilute it to a volume of 250 ml, what is the concentration of my final solution

Chemistry
1 answer:
ikadub [295]3 years ago
7 0
Equation: M1V1 = M2V2

Where M = concentration & V = volume

Step 1: Write down what is given and what you are trying to find

Given: M1 = 1.25M, V1 = 46mL, and V2 = 250mL
Find: M2

Step 2: Plug in the values into the equation

M1V1 = M2V2
(1.25M)(46mL) = (M2)(250mL)

Step 3: Isolate the variable (Divide both sides by 250mL so M2 is by itself)

(1.25M)(46mL) / (250mL) = M2

Answer: M2 = 0.23M 
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EDTA EDTA is a hexaprotic system with the p K a pKa values: p K a1 = 0.00 pKa1=0.00 , p K a2 = 1.50 pKa2=1.50 , p K a3 = 2.00 pK
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Check the explanation

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When,

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alpha[Y^{-4}] = [H+]^6 + Ka1[H+]^5 + Ka1Ka2[H+]^4 + Ka1Ka2Ka3[H+]^3 + Ka1Ka2Ka3Ka4[H+]^2 + Ka1Ka2Ka3Ka4Ka5[H+] + Ka1Ka2Ka3Ka4Ka5Ka6

= 1.26 X 10^{-61} + 1.8 X 10^{-51} + 8.1 X 10^{-43} + 1.12 X 10^{-34} + 3.17 X 10^{-27} + 3.3 X 10^{-23} + 1.83 X 10^{-23}

= 5.12 X 10^{-23}

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3 years ago
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