Missing question: <span>The liquid used in automobile cooling systems is prepared by dissolving ethylene glycol (HOCH2CH2OH) in water. Ethylene glycol has a molar mass of 62.07 g/mol and a density of 1.115 g/mL at 50.0°C.
If we use 100 mL of solution:
V(</span>ethylene glycol - C₂H₆O₂) = 0,54 · 100 mL = 54 mL.
V(water) = 0,46 · 100 mL = 46 mL.
m(C₂H₆O₂) = 54 mL · 1,115 g/mL = 60,21 g.
n(C₂H₆O₂) = 60,21 g ÷ 62,07 g/mol = 0,97 mol.
m(H₂O) = 46 mL · 0,988 g/mL = 45,45 g.
n(H₂O) = 45,45 g ÷ 18 g/mol = 2,525 mol.
mole fraction of solvent: 2,525 mol / (2,525 mol + 0,97 mol) =0,722.
Raoult's Law: p(solution) = mole fraction of solvent · p(solvent).
p(solution) = 0,722 · 92 torr = 66,42 tor.
Im more than sure that D is the only true answer. Because the root “homo” means the same, so it would only be one type (: lmk if I’m right!
It’s C. 4.68 N
I hope this helped out! Have a nice day :)
Structure along with ¹H-NMR is shown below.
Signal for Hₐ; Based on multiplicity of of the peak, a
Singlet peak (the only singlet peak present in spectrum) at
2.2 ppm was assigned to Hₐ. As the methyl group in not coupling with any other proton so it gave a singlet peak.
Signal for Hb; Based on multiplicity of of the peak, a
Quartet peak (the only quartet peak present in spectrum) at
2.4 ppm was assigned to Hb. As the methylene group in coupling with methyl group having three protons so it gave a Quartet peak.
Signal for Hc; Based on multiplicity of of the peak, a
Triplet peak (the only triplet peak present in spectrum) at
1.1 ppm was assigned to Hc. As the methyle group in coupling with methylene group having two protons so it gave a Triplet peak.