Answer:
Explanation:
The given pH = 8.55
Unknown:
[H₃O⁺] = ?
[OH⁻] = ?
In order to find these unknowns we must first establish some relationship.
pH = -log[H₃O⁺]
8.55 = -log[H₃O⁺]
[H₃O⁺] = inverse log₁₀(-8.55) = 2.82 x 10⁻⁹moldm⁻³
To find the [OH⁻],
pH + pOH = 14
pOH = 14 - pH = 14 - 8.55
pOH = 5.45
pOH = -log[OH⁻]
[OH⁻] = inverse log₁₀ (-5.45) = 3.55 x 10⁻⁶moldm⁻³
The solution is basic because it has more concentration of OH⁻ ions compared to H⁺ ions.
CH4 + 2O2 = CO2 + 2H2O
According to molar weights :
16 gm CH4 + 64 gm O2 = 44 gm CO2 + 36 gm H2O
Since 16 gm CH4 produce 36 gm H2O
Hence 2.5 gmCH4 produce 36×2.5/16 gm H2O
= 5.265 gm of H2O
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