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Pachacha [2.7K]
3 years ago
13

"Equal forces are used to move blocks A and B across the floor. Block A has twice the mass of block B, but block B moves twice t

he distance moved by block A. Which block, if either, has the greater amount of work done on it?
Physics
1 answer:
olga55 [171]3 years ago
6 0

Answer:

The work done is twice as great for block B because it is moved twice the distance of block A

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Force f⃗ =−10j^n is exerted on a particle at r⃗ =(7i^+5j^)m. part a what is the torque on the particle about the origin?
cluponka [151]

Answer:

Torque, \tau=0i+0j-70k

Explanation:

It is given that,

Force acting on the particle, F=-10j\ N

Position of the particle, r=(7i+5j)\ m

We need to find the torque on the particle about the origin. It is equal to the cross product of position and the force. Its formula is given by :

\tau=r\times F

\tau=(7i+5j)\times (-10j)

The cross product of vectors is given by :

\tau=\begin{pmatrix}0&0&-70\end{pmatrix}

or

\tau=0i+0j-70k

So, the torque on the particle about the origin 0i+0j-70k. Hence, this is the required solution.

6 0
3 years ago
A bullet is shot horizontally from shoulder height (1.5 m) with an initial speed 200 m/s. (a) How much time elapses before the b
guapka [62]
<h2>Answer: (a)t=0.553s, (b)x=110.656m</h2>

Explanation:

This situation is a good example of the projectile motion or parabolic motion, in which the travel of the bullet has two components: x-component and y-component. Being their main equations as follows:

x-component:

x=V_{o}cos\theta t   (1)

Where:

V_{o}=200m/s is the bullet's initial speed

\theta=0 because we are told the bullet is shot horizontally

t is the time since the bullet is shot until it hits the ground

y-component:

y=y_{o}+V_{o}sin\theta t-\frac{gt^{2}}{2}   (2)

Where:

y_{o}=1.5m  is the initial height of the bullet

y=0  is the final height of the bullet (when it finally hits the ground)

g=9.8m/s^{2}  is the acceleration due gravity

<h2>Part (a):</h2>

Now, for the first part of this problem, the time the bullet elapsed traveling, we will use equation (2) with the conditions given above:

0=1.5m+200m/s.sin(0) t-\frac{9.8m/s^{2}.t^{2}}{2}   (3)

0=1.5m-\frac{9.8m/s^{2}.t^{2}}{2}   (4)

Finding t:

t=\sqrt{\frac{1.5m(2)}{9.8m/s^{2}}}   (5)

Then we have the time elapsed before the bullet hits the ground:

t=0.553s   (6)

<h2>Part (b):</h2>

For the second part of this problem, we are asked to find how far does the bullet traveled horizontally. This means we have to use the equation (1) related to the x-component:

x=V_{o}cos\theta t   (1)

Substituting the knonw values and the value of t found in (6):

x=200m/s.cos(0)(0.553s)   (7)

x=200m/s(0.553s)   (8)

Finally:

x=110.656m  

4 0
4 years ago
Consider the low-speed flight of a Space Shuttle as it is nearing a landing. If the air pressure and temperature at the nose of
Nimfa-mama [501]

Answer:

d = 1.24 kg/m³

v = 0.81 m³/kg

Explanation:

To do this, we need to analyze the given data and know the expressions we need to use here to do calculations.

We have a pressure of 1.05 atm and 300 K of temperature. To determine the density, we need to use a similar expression of an ideal gas. In this case, instead of using moles, we will use density:

P = dRT

d = P/RT  (1)

Where:

R: universal constant of gases

d: density.

From here we can determine the specific volume by using the following expression:

v = 1/d   (2)

Now, as we are looking for density, we need to convert the units of pressure in atm to Pascal (or N/m) and the conversion is the following:

P = 1.05 atm * 1.013x10⁵ N/m atm = 106,365 N/m

Now, using R as 287 the density would be:

d = 106,365 / (287 * 300)

<h2>d = 1.24 kg/m³</h2>

Finally the specific volume:

v = 1 / 1.41

<h2>v = 0.81 m³/kg</h2>

Hope this helps

7 0
3 years ago
if a hydrogen atom were to absorb a small amount of energy where would bohr say the electon would go?
Vesnalui [34]
If it isn't enough energy to make the jump from 1 energy level to the next energy level, then it will go no where

7 0
4 years ago
An objects velocity will not change unless it is acted upon by ( balanced or unbalanced) forces?
OlgaM077 [116]
" An object<span> at rest stays at rest and </span>an object <span>in motion stays in motion with the same speed and in the same direction </span>unless acted upon<span> by an </span>unbalanced force<span>."- Newtons first Law of Motion

Also, velocity is the speed of something in a given direction (So, 50mph North is an example of velocity)</span>
7 0
4 years ago
Read 2 more answers
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