Answer:
3 AU
Explanation:
We can solve the problem by using Kepler's third law, which states that the ratio between the cube of the orbital radius and the square of the orbital period is constant for every object orbiting the Sun. So we can write

where
is the distance of the asteroid from the sun (orbital radius)
is the orbital period of the asteroid
is the orbital radius of the Earth
is the orbital period the Earth
Solving the equation for
, we find
![r_a = \sqrt[3]{\frac{r_e^3}{T_e^2}T_a^2} =\sqrt[3]{\frac{(1 AU)^3}{(1 y)^2}(5.2 y)^2}=3 AU](https://tex.z-dn.net/?f=r_a%20%3D%20%5Csqrt%5B3%5D%7B%5Cfrac%7Br_e%5E3%7D%7BT_e%5E2%7DT_a%5E2%7D%20%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B%281%20AU%29%5E3%7D%7B%281%20y%29%5E2%7D%285.2%20y%29%5E2%7D%3D3%20AU)
So, the distance of the asteroid from the Sun is exactly 3 times the distance between the Earth and the Sun.
Answer:
Frequency.
Explanation:
Sound are mechanical waves that are highly dependent on matter for their propagation and transmission.
Sound travels faster through solids than it does through either liquids or gases. A student could verify this statement by measuring the time required for sound to travel a set distance through a solid, a liquid, and a gas.
Mathematically, the speed of a sound is given by the formula:
Speed = wavelength * frequency
The pitch of a sound you hear depends on the frequency of the sound wave.