Answer:
The normal force applied by block on the ground is (mg - F cosФ)
Explanation:
<em>Lets explain how to solve the problem</em>
At first you must distribute the force F into two components
<em>Vertical</em> component which is <em>F cosФ</em>
<em>Horizontal</em> component which is <em>F sinФ</em>
The block is in equilibrium, that means sum of forces acting on the
block is zero
So the upward forces equal the downward forces
Normal reaction force R applied by block on the ground and the
vertical component of F both are upward forces
The weight of the block is downward force
The normal reaction force R plus the vertical component of F is
equal to the weight
<em>R + F cosФ = W</em>
W = mg, where g is acceleration of gravity and m is the mass of
the block
<em>R + F cosФ = mg</em>
Subtract F cosФ from both sides
<em>R = mg - F cosФ</em>
<em></em>
The normal force applied by block on the ground is (mg - F cosФ)
