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4 years ago

In the given arrangement, the normal force applied by block on the ground is

Physics

1 answer:

barxatty [35]4 years ago

7 0

Answer:

The normal force applied by block on the ground is (mg - F cosФ)

Explanation:

Lets explain how to solve the problem

At first you must distribute the force F into two components

Vertical component which is F cosФ

Horizontal component which is F sinФ

The block is in equilibrium, that means sum of forces acting on the

block is zero

So the upward forces equal the downward forces

Normal reaction force R applied by block on the ground and the

vertical component of F both are upward forces

The weight of the block is downward force

The normal reaction force R plus the vertical component of F is

equal to the weight

R + F cosФ = W

W = mg, where g is acceleration of gravity and m is the mass of

the block

R + F cosФ = mg

Subtract F cosФ from both sides

R = mg - F cosФ

The normal force applied by block on the ground is (mg - F cosФ)

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2 years ago

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3 years ago

Determine the momentum of a 6 kg object moving at 5 m.s-1 to the right

SCORPION-xisa [38]

Answer:

P = 6*5 = 30 [kg*m/s]

Explanation:

in order to solve this problem, we must remember that linear momentum is defined as the product of mass by Velocity. This way you can calculate the momentum using the following equation.

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3 years ago

An office worker uses an immersion heater to warm 237 g of water in a light, covered, insulated cup from 20°C to 100°C in 6.00 m

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Answer:

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(a)

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3 years ago

In the given arrangement, the normal force applied by block on the ground is​

In the given arrangement, the normal force applied by block on the ground is