Answer:
solution:-We know that for any two finite sets A and B, n(A∪B)=n(A)+n(B)−n(A∩B).
Here, it is given that n(A)=20,n(B)=30 and n(A∪B)=40, therefore,
n(A∪B)=n(A)+n(B)−n(A∩B)
⇒40=20+30−n(A∩B)
⇒40=50−n(A∩B)
⇒n(A∩B)=50−40
⇒n(A∩B)=10
Hence, n(A∩B)=10
Step-by-step explanation:
hope it helps you friend ☺️
Answer:
ok
Step-by-step explanation:
ok
Answer:
9.3 hours
Step-by-step explanation:
Given
![y = 2.89\sin(0.0145x-1.40) + 10.99.](https://tex.z-dn.net/?f=y%20%3D%202.89%5Csin%280.0145x-1.40%29%20%2B%2010.99.)
Required
Hours of sunlight on Feb 21, 2013
First, calculate the number of days from Jan 1, 2013 to Feb 21, 2013
![days = 52](https://tex.z-dn.net/?f=days%20%3D%2052)
So:
![x = 52](https://tex.z-dn.net/?f=x%20%3D%2052)
So, we have:
![y = 2.89\sin(0.0145x-1.40) + 10.99.](https://tex.z-dn.net/?f=y%20%3D%202.89%5Csin%280.0145x-1.40%29%20%2B%2010.99.)
![y = 2.89\sin(0.0145*52-1.40) + 10.99.](https://tex.z-dn.net/?f=y%20%3D%202.89%5Csin%280.0145%2A52-1.40%29%20%2B%2010.99.)
![y = 2.89\sin(0.754-1.40) + 10.99.](https://tex.z-dn.net/?f=y%20%3D%202.89%5Csin%280.754-1.40%29%20%2B%2010.99.)
![y = 2.89\sin(-0.646) + 10.99.](https://tex.z-dn.net/?f=y%20%3D%202.89%5Csin%28-0.646%29%20%2B%2010.99.)
![y = 2.89*-0.6020 + 10.99.](https://tex.z-dn.net/?f=y%20%3D%202.89%2A-0.6020%20%2B%2010.99.)
![y = -1.740 + 10.99.](https://tex.z-dn.net/?f=y%20%3D%20-1.740%20%2B%2010.99.)
![y = 9.25](https://tex.z-dn.net/?f=y%20%3D%209.25)
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<em> --- approximated</em>
There are 3 terms. Because if you simplify it, 7x and 2x would be 9x.. and -5+11 would be 6 so there would be (9x+3y+6) left. so 3 terms