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GalinKa [24]
3 years ago
6

Is y=-5/6x proportional?

Mathematics
1 answer:
lys-0071 [83]3 years ago
7 0

Answer:

no

Step-by-step explanation:

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Help! 10 Points not 5!
KATRIN_1 [288]

9514 1404 393

Answer:

  18

Step-by-step explanation:

Solve the first for a, then substitute into the second.

  a = 27/(5b^2)

Then ...

  (27/(5b^2))^2·b = 135

  27^2/(5^2·135) = b^3 = 27/125

  b = ∛(27/125) = 3/5

  a = 27/(5(3/5)^2) = 15

__

The expression of interest is ...

  a +5b = 15 + 5(3/5) = 15 +3

  a +5b = 18

6 0
3 years ago
 You buy 3.17 pounds of peaches​, 1.45 pounds of apples​, and 1.85 pounds of oranges. What is your total​ bill?
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4 years ago
Next telephone company charges $0.07 Per minute for a weekend calls and $0.09 Per minute for calls made on weekdays. This month
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You should suck a long rod and the answer is around 50 minutes
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3 years ago
Simplify<br> 7x + 2y - 3x + 4y<br><br> Factorise<br> 10x - 15<br><br> Solve<br> 5p = 3p + 8
vlada-n [284]

Answer:

1. x = -1.5y

2. 5 (2x-3)

3. p = 4

Step-by-step explanation:

1) Simplifying

7x + 2y + -3x + 4y = 0

Reorder the terms:

7x + -3x + 2y + 4y = 0

Combine like terms: 7x + -3x = 4x

4x + 2y + 4y = 0

Combine like terms: 2y + 4y = 6y

4x + 6y = 0

Solving

4x + 6y = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-6y' to each side of the equation.

4x + 6y + -6y = 0 + -6y

Combine like terms: 6y + -6y = 0

4x + 0 = 0 + -6y

4x = 0 + -6y

Remove the zero:

4x = -6y

Divide each side by '4'.

x = -1.5y

Simplifying

x = -1.5y

2)

Common factor

10x - 15

5 (2x-3)

3) Simplifying

5p = 3p + 8

Reorder the terms:

5p = 8 + 3p

Solving

5p = 8 + 3p

Solving for variable 'p'.

Move all terms containing p to the left, all other terms to the right.

Add '-3p' to each side of the equation.

5p + -3p = 8 + 3p + -3p

Combine like terms: 5p + -3p = 2p

2p = 8 + 3p + -3p

Combine like terms: 3p + -3p = 0

2p = 8 + 0

2p = 8

Divide each side by '2'.

p = 4

Simplifying

p = 4

7 0
3 years ago
A. Name 3 different angles which could have a reference angle of 20 degrees. How did you arrive at this answer?.
IgorC [24]

<u>Answer:</u>

<u>Answer:a. Since 20° is in the first quadrant, the reference angle is 20° .</u>

<u>Answer:a. Since 20° is in the first quadrant, the reference angle is 20° .b. Reference Angle: the acute angle between the terminal arm/terminal side and the x-axis. The reference angle is always positive. In other words, the reference angle is an angle being sandwiched by the terminal side and the x-axis. It must be less than 90 degree, and always positive.</u>

<u>Answer:a. Since 20° is in the first quadrant, the reference angle is 20° .b. Reference Angle: the acute angle between the terminal arm/terminal side and the x-axis. The reference angle is always positive. In other words, the reference angle is an angle being sandwiched by the terminal side and the x-axis. It must be less than 90 degree, and always positive.c. The rays corresponding to supplementary angles intersect the unit circles in points having the same y-coordinate, so the two angles have the same sine (and opposite cosines).</u>

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<em>Z</em><em>a</em><em>r</em><em>a</em><em>♡</em>

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3 years ago
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