There are no coordinates for an equation like this, you have to just graph the problem. Just try graphing something similar to this (or just include this image). Hope this helps!
It's the last option again. You have 1 linear factor (3<em>x</em>) and 2 copies of a quadratic factor (<em>x</em>² + 10), and the partial fractions with the quadratic factor need to have a linear polynomial in the numerator.
Angles 1,7 and 2,8 are alternate exterior angle.
28/11.2 = 2.5
since they are similar and openly stated as parrallelograms, you know that they have a scale of the longest edge of EFGH to the longest edge of JKLM
Answer:
False
Step-by-step explanation:
I would say false;
This graph is really hard to read because of the way it's subdivided but one of the coordinate points is (0,-1) and the line clearly passes through the origin (0,0).
If you have the chance, please tell your teacher to provide better graphs that are actually readable.
