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Vlada [557]
3 years ago
11

Systems of linear equations ; elimination method pls help<3

Mathematics
1 answer:
Basile [38]3 years ago
6 0
<h3>Answer:</h3>

System

  • 10s +25t = 11700
  • s -2t = 0

Solution

  • s = 520
  • t = 260
<h3>Explanation:</h3>

Let s and t represent single-entry and three-day tickets, respectively. These variables represent the numbers we're asked to find: "how many of each [ticket type] he sold."

We are given the revenue from each ticket type, and the total revenue, so we can write an equation based on the relation between prices, numbers sold, and revenue:

... 10s +25t = 11700 . . . . . equation for total revenue

We are also given a relation between the two number of tickets sold:

... s = 2t . . . . . . . . . . . . . . . twice as many single tickets were sold as 3-day

We can rearrange this second equation to put it into standard form. That makes it easier to see what to do to eliminate a variable.

... s -2t = 0 . . . . . . . . . . . . subtract 2t to put into standard form

So, our system of equations is ...

  • 10s +25t = 11700
  • s -2t = 0

<em>What </em>elimination<em> is all about</em>

The idea with "elimination" is to find a multiple of one (or both) equations such that the coefficients of one of the variables are opposite. Then, the result of adding those multiples will be to eliminate that variable.

Here, we can multiply the second equation by -10 to make the coefficient of s be -10, the opposite of its value in the first equation. (We could also multiply the first equation by -0.1 to achieve the same result. This would result in a non-integer value for the coefficient of t, but the solution process would still work.)

Alternatively, we can multiply the first equation by 2 and the second equation by 25 to give two equations with 50t and -50t as the t-variable terms. These would cancel when added, so would eliminate the t variable. (It seems like more work to do that, so we'll choose the first option.)

<em>Solution by elimination</em>

... 10s +25t = 11700 . . . . our first equation

... -10s +20t = 0 . . . . . . . second equation of our system, multiplied by -10

... 45t = 11700 . . . . . . . . .the sum of these two equations (s-term eliminated)

... t = 11700/45 = 260 . . . . . divide by the coefficient of t

... s = 2t = 520 . . . . . . . . . . use the relationship with s to find s

_____

<em>Solution using your number sense</em>

As soon as you see there is a relation between single-day tickets and 3-day tickets, you can realize that all you need to do is bundle the tickets according to that relation, then find the number of bundles. Here, 2 single-day tickets and 1 three-day ticket will bundle to give a package worth 2×$10 + $25 = $45. Then the revenue of $11700 will be $11700/$45 = 260 packages of tickets. That amounts to 260 three-day tickets and 520 single-day tickets.

(You may notice that our elimination solution effectively computes this same result, where "t" and the number of "packages" is the same value (since there is 1 "t" in the package).)

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Write an equation that represents the line.<br> Use exact numbers.
mariarad [96]

Answer:

y = .75x - 4.5

Step-by-step explanation:

y = mx + b

m = slope ; b = y-int

slope = rise/ run = 3/4 = .75

y = .75x + b

Because it is hard to determine the exact y-intercept, we plug in a point (2,-3):

-3 = .75(2) + b

-3 = 1.5 + b

-4.5 = b -->

y = .75x - 4.5

5 0
3 years ago
Heidi solved the equation 3(x + 4) + 2 = 2 + 5(x – 4). Her steps are below: 3x + 12 + 2 = 2 + 5x – 20 3x + 14 = 5x – 18 14 = 2x
saveliy_v [14]

step 1: distributive property.

step 2: combine like terms.

step 3: subtraction property of equality.

step 4: addition property of equality.

step 5: division property of equality.  

hope this helps.

3 0
2 years ago
Read 2 more answers
1.Sam has a piggy bank full of quarters, dimes, nickels, and pennies. Describe two ways he could make $0.78 using only two kinds
insens350 [35]
3 quarters and 3 pennies, or 7 dimes 1 nickel and 3 pennies

Hope this helps

6 0
3 years ago
Read 2 more answers
Please help me answer 5 and 6.
Kryger [21]
For number 5 you are just multiplying by 4.5
5 0
3 years ago
Can anyone please help me with this ?
djverab [1.8K]

Answer:

The distance from point A to the top of the building is 5\sqrt{2} feet

The Height of the Skyscraper is 5 feet

Step-by-step explanation:

Given

Let Top point of building be point C

Also Let Base of the building be point  B

Distance from point A to base B of the building AB= 5 feet

∴ It makes a Right angle triangle

Also ∠ACB = 45°

Also tan 45° = 1

Now tan ∠ACB =\frac{AB}{BC}

∴ AB= BC =5 feet

The Height of the Skyscraper is 5 feet

Now Triangle ABC is right angle triangle with right angled at B

So by Pythagoras theorem

AC= \sqrt{AB^2+BC^2}=\sqrt{5^2+5^2} =\sqrt{50} =\sqrt{25\times2} =\sqrt{5^2\times2}=5\sqrt{2}

The distance from point A to the top of the building is 5\sqrt{2} feet

5 0
3 years ago
Read 2 more answers
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