Question

Assume that a cross is made between a heterozygous tall pea plant and a homozygous short pea plant. Fifty offspring are produced in the following frequency:30 = tall20 = shortNull hypothesis: The deviations from a 1:1 ratio (25 tall and 25 short) are due to chance.What is the Chi-square value associated with the appropriate test of significance?

Answer 1

Answer:

Chi-square value = 2

Step-by-step explanation:

Given data:

Frequency:      Tall     Short

                         30       20

Null hypothesis ( as it is already given so there is no difference between observed and expected values)

Ratio:    1:1 (50% expected frequency of each tall and short pea-plant)

Solution:

Phenotype  Observed  Expected O-E  (O-E)²  (O-E)$^{2/E}$

                          O                  E

Short                20               25        -5       25        1                          

TALL                  30               25         5        25       1

TOTAL                                                                       2

So, from all these calculations using expected and observed values we get chi-square value equal to 2.