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Oduvanchick [21]
3 years ago
13

Write an estimate that will show if 77 is a reasonable solution the equation 14+m=91

Mathematics
2 answers:
Jobisdone [24]3 years ago
4 0
The answer to this problem is 83
BARSIC [14]3 years ago
3 0
91-14=77
you take the two answers you got to find the missing number
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Donnie's dad is 3 times older than Donnie, and the sum of their ages is no less than 56. What is the youngest that Donnie can be
Gala2k [10]

Answer:

14

Step-by-step explanation:

If Donnie is 3 times younger than Donnie's dad, that adds up to four parts. In other words, Donnie is 1/4 his dads age. So, divide 56 by four and you have Donnie's age. The rest is Donnie's dad age.

4 0
3 years ago
BRAINLIEST, JUST SAY THE ANSWER
sertanlavr [38]

Answer:

4/16

Step-by-step explanation:

pls give me brainliest

4 0
3 years ago
Read 2 more answers
Application of Trigonometric Ratios:
Irina-Kira [14]

9514 1404 393

Answer:

  15.46 m

Step-by-step explanation:

Side ratios of a 30°-60°-90° triangle are 1 : √3 : 2. That is, the height of the tree above eye-height is √3 times the distance from the trunk. The top of the crown will be at a height of ...

  1.6 m + (8 m)√3 ≈ 15.46 m

5 0
3 years ago
Let v1=(3,5) and v2=(-4,7) Compute the unit vectors in the direction of |v1| and |v2|?
AleksandrR [38]
By definition, the unit vector of v = (a,b) is
\hat{v} =  \frac{\vec{v}}{|v|}

Therefore,
The unit vector of v₁ = (3,5) in the direction of |v₁| s
 (3,5)/√[3² + 5²]
= (3,5)/√34

The unit vector of v₂ in the direction of |v₂| is
(-4,7)/√[(-4)² + 7²]
= (-4,7)/√65

Answer:
The unit vector of v₁ in the direction of |v₁} is ( \frac{3}{\sqrt{34}} ,  \frac{5}{\sqrt{34}} )
The unit vector of v₂ in the directin of |v₂| is
( \frac{-4}{\sqrt{65}} , \frac{7}{\sqrt{65}} )

6 0
4 years ago
Which numbers are 4 units from -2 on the number line
Artemon [7]

Let the number be x


Then the absolute value of the number from -2 should be 4


|x--2|=4


|x+2|=4


So either



(x+2)=4


x=4-2=2


Or


-(x+2)=4


x+2=-4



x=-4-2



x=-6



[tex] <B>The numbers are 2 and -6</B> [/tex[


They are four units away from -2 on the number line










4 0
3 years ago
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