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OverLord2011 [107]
3 years ago
6

Let v1=(3,5) and v2=(-4,7) Compute the unit vectors in the direction of |v1| and |v2|?

Mathematics
1 answer:
AleksandrR [38]3 years ago
6 0
By definition, the unit vector of v = (a,b) is
\hat{v} =  \frac{\vec{v}}{|v|}

Therefore,
The unit vector of v₁ = (3,5) in the direction of |v₁| s
 (3,5)/√[3² + 5²]
= (3,5)/√34

The unit vector of v₂ in the direction of |v₂| is
(-4,7)/√[(-4)² + 7²]
= (-4,7)/√65

Answer:
The unit vector of v₁ in the direction of |v₁} is ( \frac{3}{\sqrt{34}} ,  \frac{5}{\sqrt{34}} )
The unit vector of v₂ in the directin of |v₂| is
( \frac{-4}{\sqrt{65}} , \frac{7}{\sqrt{65}} )

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What is the value of 1 tens and 16 ones
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3 0
2 years ago
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A simple random sample of items resulted in a sample mean of . The population standard deviation is . a. Compute the confidence
Varvara68 [4.7K]

Answer:

(a): The 95% confidence interval is (46.4, 53.6)

(b): The 95% confidence interval is (47.9, 52.1)

(c): Larger sample gives a smaller margin of error.

Step-by-step explanation:

Given

n = 30 -- sample size

\bar x = 50 -- sample mean

\sigma = 10 --- sample standard deviation

Solving (a): The confidence interval of the population mean

Calculate the standard error

\sigma_x = \frac{\sigma}{\sqrt n}

\sigma_x = \frac{10}{\sqrt {30}}

\sigma_x = \frac{10}{5.478}

\sigma_x = 1.825

The 95% confidence interval for the z value is:

z = 1.960

Calculate margin of error (E)

E = z * \sigma_x

E = 1.960 * 1.825

E = 3.577

The confidence bound is:

Lower = \bar x - E

Lower = 50 - 3.577

Lower = 46.423

Lower = 46.4 --- approximated

Upper = \bar x + E

Upper = 50 + 3.577

Upper = 53.577

Upper = 53.6 --- approximated

<em>So, the 95% confidence interval is (46.4, 53.6)</em>

Solving (b): The confidence interval of the population mean if mean = 90

First, calculate the standard error of the mean

\sigma_x = \frac{\sigma}{\sqrt n}

\sigma_x = \frac{10}{\sqrt {90}}

\sigma_x = \frac{10}{9.49}

\sigma_x = 1.054

The 95% confidence interval for the z value is:

z = 1.960

Calculate margin of error (E)

E = z * \sigma_x

E = 1.960 * 1.054

E = 2.06584

The confidence bound is:

Lower = \bar x - E

Lower = 50 - 2.06584

Lower = 47.93416

Lower = 47.9 --- approximated

Upper = \bar x + E

Upper = 50 + 2.06584

Upper = 52.06584

Upper = 52.1 --- approximated

<em>So, the 95% confidence interval is (47.9, 52.1)</em>

Solving (c): Effect of larger sample size on margin of error

In (a), we have:

n = 30     E = 3.577

In (b), we have:

n = 90    E = 2.06584

<em>Notice that the margin of error decreases when the sample size increases.</em>

4 0
3 years ago
What is 100×3857×29473
marshall27 [118]
The answer is 11367736100!
3 0
3 years ago
Read 2 more answers
I don't know this. Its part of my math homework. 5^9x6/700(3^3)/90+600-9000/5000
Zigmanuir [339]

Answer:

5620.52142857

Step-by-step explanation:

Rounded 5620.52

Your Welcome : )

4 0
3 years ago
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