The initial population size can be found by substituting values for "T"
At time zero, there are no birds because
·(2×0)×100=0
At time 1 there would be 200 birds this is because
·(2×1)×100=200
And the start besides time Zero would be at time 1, there for the initial population would be represented by the population at time 1, which is 200.
In conclusion the initial population in this equation would be 200.
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2x-3y=12
4x+3y=24
6x=36
x=6
2(6)+3y=12
12+3y=12
y=0
(6,0)
<h2>
Answer:</h2>
The answer is 16.
<h2>
Step-by-step explanation:</h2>
Since the 8x is positive, the equation must have y as a positive number.
Let's see this!
An easy way to complete the square if you have the constants for x2 and
But not the non-variable number is to divide the x constant, and then square it.
Example:

The last number must be 16. Let's check it.

There is no picture, but you would substitute the first number for the x and the second for the y
Answer:
its c)
Step-by-step explanation:
just looked it up