<span>Given: Rectangle ABCD
Prove: ∆ABD≅∆CBD
Solution:
<span> Statement Reason
</span>
ABCD is a parallelogram Rectangles are parallelograms since the definition of a parallelogram is a quadrilateral with two pairs of parallel sides.
Segment AD = Segment BC The opposite sides of a parallelogram are Segment AB = Segment CD congruent. This is a theorem about the parallelograms.
</span>∆ABD≅∆CBD SSS postulate: three sides of ΔABD is equal to the three sides of ∆CBD<span>
</span><span>Given: Rectangle ABCD
Prove: ∆ABC≅∆ADC
</span>Solution:
<span> Statement Reason
</span>
Angle A and Angle C Definition of a rectangle: A quadrilateral
are right angles with four right angles.
Angle A = Angle C Since both are right angles, they are congruent
Segment AB = Segment DC The opposite sides of a parallelogram are Segment AD = Segment BC congruent. This is a theorem about the parallelograms.
∆ABC≅∆ADC SAS postulate: two sides and included angle of ΔABC is congruent to the two sides and included angle of ∆CBD
Answer:
Clara can feed 10 friend
I may be wrong, but I tried :P
First plot the points. Let’s just use the first graph. When you have done that. Draw a triangle. Find the right angle and look at what line is across from that. That is the hypotenuse. That is the length that you are trying to find. So you have to do your equation: a^2 + b^2 = c^2. A and B have to be the length of the other 2 lines(just count it). When you have done that repack you a and b with your #s. And what ever is equal to you c. Then that is you answer. (Im sorry if this was confusing)
Equilateral, because the sides are equal
