Until 2015, each new Roblox user automatically had one friend and the friend was called Builderman
Builderman is the friend that is provided automatically for all users until 2015
<h2>Further Explanation</h2>
The builderman welcomes each new Roblox user, send a message to them and automatically follows every user until when it was discontinued in 2014. The role of the Builderman was to introduce the game experience to each new Roblox user.
Roblox is an online game and serves as a platform where users can also create their own games. Roblox gives its users the platform to design their own games and allow its user to different kinds of games that are created by other users on the platform
Roblox hosts numerous games designed by its users and virtual worlds which covers different genres, such as traditional racing, obstacle courses and many more.
Roblox has millions of users worldwide, its monthly active users are over 100million. Roblox also allows its users to create virtual items for sale. This also implies, its users can create virtual items and sell them for other users
Roblox was founded by David Baszucki and Erik Cassel; it was released on September 1, 2006. It is a platform that allows single-player and multiplayer.
LEARN MORE:
KEYWORDS:
- roblox
- builderman
- friend
- message
- automatically
- david baszucki
- erik cassel
Answer:
1) pull out the legs of the tripod to gain the required height and necessary stability
2) adjust each of the legs so that the tripod is level
3) attach the camera to the tripod
Since both arrays are already sorted, that means that the first int of one of the arrays will be smaller than all the ints that come after it in the same array. We also know that if the first int of arr1 is smaller than the first int of arr2, then by the same logic, the first int of arr1 is smaller than all the ints in arr2 since arr2 is also sorted.
public static int[] merge(int[] arr1, int[] arr2) {
int i = 0; //current index of arr1
int j = 0; //current index of arr2
int[] result = new int[arr1.length+arr2.length]
while(i < arr1.length && j < arr2.length) {
result[i+j] = Math.min(arr1[i], arr2[j]);
if(arr1[i] < arr2[j]) {
i++;
} else {
j++;
}
}
boolean isArr1 = i+1 < arr1.length;
for(int index = isArr1 ? i : j; index < isArr1 ? arr1.length : arr2.length; index++) {
result[i+j+index] = isArr1 ? arr1[index] : arr2[index]
}
return result;
}
So this implementation is kind of confusing, but it's the first way I thought to do it so I ran with it. There is probably an easier way, but that's the beauty of programming.
A quick explanation:
We first loop through the arrays comparing the first elements of each array, adding whichever is the smallest to the result array. Each time we do so, we increment the index value (i or j) for the array that had the smaller number. Now the next time we are comparing the NEXT element in that array to the PREVIOUS element of the other array. We do this until we reach the end of either arr1 or arr2 so that we don't get an out of bounds exception.
The second step in our method is to tack on the remaining integers to the resulting array. We need to do this because when we reach the end of one array, there will still be at least one more integer in the other array. The boolean isArr1 is telling us whether arr1 is the array with leftovers. If so, we loop through the remaining indices of arr1 and add them to the result. Otherwise, we do the same for arr2. All of this is done using ternary operations to determine which array to use, but if we wanted to we could split the code into two for loops using an if statement.
Answer:
With drag-and-drop editing, word automatically displays a paste options button near the pasted or moved text.
Explanation:
<u>Option A:</u> Cut and paste option is invalid because, cut and paste option does not provide paste symbol near the copied text. This option and cut and paste a selected text.
<u> Option C :</u> Inline is invalid in this context
<u>Option D: </u>Copy and Carry is not valid because the option “copy” is available where as carry is not available.
<u>Option B:</u> Drag and drop is the right answer because, it provides paste option by using this feature. A text can be drag and drop by selecting the text and dragging the mouse with the left click