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4 years ago

What is the equivalent fraction for 6 2/5

2 answers:

8 0

What you have to do here is do 6x5 to give you 30 and add it to the numerator to give you 32. Then put it over 5 to give 32/5

UkoKoshka [18]4 years ago

4 0

Solve:-

6 2/5

5 × 6 = 35
35 + 2 = 38

38 = numerator
5 = denominator
38/5

6 2/5 = 38/5

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I need help to Find z =

lina2011 [118]

Answer:

Z = 110

Step-by-step explanation:

Since the figures are similar, the angles have to be equal

<A = <E

<B = <F

<C = <G

<D = <H

<D = 110 so angle <H = 110

Z = 110

5 0

3 years ago

Bob eats 1/4 ounce of cheese. One serving of cheese is 1 1/2 ounces. How much of a serving did he eat?

katen-ka-za [31]

Answer:

1/6 serving

Step-by-step explanation:

1 SERVING = 3/2 OUNCES

x = 1/4 OUNCES

CROSS MULTIPLY.

1 * 1/4 ( serving * ounces) = x * 3/2 (ounces)

REARRANGE, THEN DIVIDE BOTH SIDES BY 3/2 OUNCES TO MAKE x THE SUBJECT.

x * 3/2 (ounces) = 1 * 1/4 ( serving * ounces)

[x * 3/2 (ounces)] / 3/2 OUNCES = [1 * 1/4 ( serving * ounces)] / 3/2 OUNCES

x = (1/4) / (3/2) SERVING

x = 1/4 * 2/3 (serving)

x = 1/2 * 1/3 (serving)

x = 1/6 serving

Please thank, rate 5 stars and give brainliest. Thank you. i hope you understand!

6 0

3 years ago

Marking brainliest Please help

Katen [24]

The answer is lad missed lady plz brainliest

6 0

3 years ago

A farmer uses 1/3 of his land to plant cassava, 2/5 of the remaining and to plant maize and the rest vegetables.if vegetables co

abruzzese [7]

Cassava = 1/3 of his land

Remaining after planting Cassava = 1 - 1/3 = 2/3 of his land

Maize = 2/5 x 2/3 = 4/15 of his land

Vegetables = 2/3 - 4/15 = 2/5 of his land

If vegetables = 10 acres

2/5 of his land = 10 acres

1/5 of his land = 10 ÷ 2 = 5 acres

5/5 of his land = 5 x 5 = 25 acres

Answer: Total area 25 acres.

6 0

3 years ago

Which products result in a sum or difference of cubes? Check all that apply. (x – 4)(x2 + 4x – 16) (x – 1)(x2 – x + 1) (x – 1)(x

olchik [2.2K]

$a^3+b^3=(a+b)(a^2-ab+b^2)\\\\a^3-b^3=(a-b)(a^2+ab+b^2)\\\\(x-4)(x^2+4x\underline{-16})\qquad \mathbb{NOT}\\\\(x-1)(x^2\underline{-x}+1)\qquad\mathbb{NOT}\\\\(x-1)(x^2+x+1)=(x-1)(x^2+(x)(1)+1^2)\qquad\mathbb{YES}\\\\(x+1)(x^2+x\underline{-1})\qquad\mathbb{NOT}\\\\(x+4)(x^2-4x+16)=(x+4)(x^2+(x)(4)+4^2)\qquad\mathbb{YES}\\\\(x+4)(x^2\underline{+4x}+4)\qquad\mathbb{NOT}$

8 0

3 years ago

Read 2 more answers