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3 years ago

You have a jar containing 55 coins, consisting entirely of nickels and quarters, worth a

Mathematics

1 answer:

yawa3891 [41]3 years ago

6 0

Answer: 22 quarters

Step-by-step explanation:

Let N be the number of nickels.

Then the number of quarters is (55-N)

The nickels contribute 5N cents to the total.

The quarters contribute 25*(55-N) cents to the total.

5N + 25*(55-N) = 715

5N + 1375 - 25N = 715

-20N = 715 - 1375 = -660

$N=\frac{-660}{-20}$

$=33$

$55-33=22$

So there is 22 quarters inside the jar.

Check to see if my answer is correct-

33*5 + 22*25 = 715 cents

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