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3 years ago

Find the dimensions of a rectangle whose perimeter is 42 m and whose area is 104 m squared

1 answer:

6 0

P=42 m
1/2 of P=21
1/2 of P= l+w
21=13+8
A=13×8
A=104 m^2. As a result, the length is 13 m, and the width is 8 m. Hope it help!

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