Answer:
The answer is B
The greatest number of rides Daniel can go on is 20.
Step-by-step explanation:
Total: The same or less than 40
Fair Admission: 10
ride: 1.50x
40 ≤ 10 + 1.5r
To solve:
40 ≤ 10 + 1.5r
40 - 10 ≤ 10 + 1.5r - 10
30 ≤ 1.5r
30 ÷ 1.5 ≤ 1.5r ÷ 1.5
20 ≤ r
The greatest number of rides Daniel can go on is 20.
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Answer:
Step-by-step explanation:
(-3/4)^-4 = (-4/3)^4 = (4/3)^4
Answer: 1 1/15
Step-by-step explanation:
9/10 = 27/30
1/6= 5/30
27/30-5/30=32/30
32/30=1 2/30 which be simplified to 1 1/15
64/33 = x /16
x = (64*16) / 33 = 31.03 to nearest hundredth
