Question

What is the solution to this system of linear equations? X-3y=-2 and x-3y=16

Answer 1

Answer:

No solution

Step-by-step explanation:

Equations:

x - 3y = -2

x - 3y = 16

Subtract:

0 - 0 = -18

Answer:

No solution

Answer 2

Answer:

NO SOLUTION

Step-by-step explanation:

Two equations of the system of linear equations has been given as x - 3y = -2 and x - 3y = 16

if we see in these equations slopes are same for both.

x - 3y = -2

+3y = +2 +x

y = $\frac{1}{3}$x + $\frac{2}{3}$

slope m₁ = $\frac{1}{3}$

x - 3y = 16

-3y = 16-x

3y = x - 16

y = $\frac{1}{3}$x - $\frac{16}{3}$

slope m₂ = $\frac{1}{3}$

so m₁ = m₂ = $\frac{1}{3}$

These lines are parallel to each other.

Since parallel lines don't intersect each other so there is NO SOLUTION for this system of equation.