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3 years ago

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Valeria drew a scale drawing of a farm. The goat pen, which is 20 meters long in real life, is 5 millimeters long in the drawing

. What is the scale of the drawing?

1 answer:

Vera_Pavlovna [14]3 years ago

8 0

Drew scale of the drawing of a farm

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1/2 of 30 = 1/4 of ??

Leto [7]

Answer:60

Step-by-step explanation:

⅟₂ of 30=15

¼ of 60=15

<h3>Half of thirty is 15 so u need to know what ¼ of something makes 15 so all u have to do is times 15 by 4 and there got ur answer this will not go for every question tho</h3>

4 0

3 years ago

What is the equation of the line that passes through the point (-6, -6) and has a<br> slope of - 1/3

pickupchik [31]

Answer:

The equation of the line is $y = -\frac{1}{3}x - 8$

Step-by-step explanation:

Equation of a line:

The equation of a line has the following format:

$y = mx + b$

In which m is the slope and b is the y-intercept.

Slope of - 1/3

This means that $m = -\frac{1}{3}$

So

$y = -\frac{1}{3}x + b$

Through the point (-6, -6)

This means that when $x = -6, y = -6$ . So

$y = -\frac{1}{3}x + b$

$-6 = -\frac{1}{3}(-6) + b$

$b + 2 = -6$

$b = -8$

The equation of the line is $y = -\frac{1}{3}x - 8$

5 0

3 years ago

1. A local pizzeria sold 70 pizzas yesterday.

just olya [345]

Answer:

1. 91 = 70*1.30

2a. 195= 150*1.30

2b. 210 = 150*1.40

3a. 56.70 = 156* .30

3b. 132.30 = 156-56.70

3c. 17.20 = 132.30 *0.13

3d. 149.50 = 132.30+17.20

3e. You do not have enough money, because you need $9.50 more.

Step-by-step explanation:

good luck

5 0

3 years ago

Read 2 more answers

Two forces with magnitudes of 150 and 100 pounds act on an object at angles of 30° and 120°, respectively. Find the direction an

lyudmila [28]

<h2>Answer:</h2>

$Magnitude=180.27 \ lbf \\ \\ Direction=63.69 \ degrees$

<h2>Step-by-step explanation:</h2>

We have two forces as follows:

<u>First force:</u>

Magnitude: 150 pounds

Angle: 30°

<u>First force:</u>

Magnitude: 100 pounds

Angle: 120°

So the components can be found as follows:

$F_{1x}=150cos(30)=129.90 \ lbf\\F_{1y}=150sin(30) = 75 \ lbf \\ \\ F_{2x}=100cos(120)=-50 \ lbf\\F_{2y}=100sin(120) = 86.60 \ lbf$

So the components of the resultant force can be found by adding each component of the individual forces as follows:

$R_{x}=\Sigma F_{x} \\ R_{y}=\Sigma F_{y} \\ \\ R_{x}=129.90-50=79.90 \ lbf \\ R_{y}=75+86.60=161.6 \ lbf$

Finally, the magnitude and direction of the resultant force is:

$Magnitude \rightarrow R=\sqrt{R_{x}^2+R_{y}^2}=\sqrt{79.90^2+161.6^2}=180.27 \ lbf \\ \\ Direction \rightarrow \theta=tan^{-1}(\frac{R_{y}}{R_{x}})=tan^{-1}(\frac{161.6}{79.90})=63.69 \ degrees$

6 0

3 years ago

Read 2 more answers

Make x the subject. <br>1) а — x =y<br>2) m = k – x <br>3) k - t2x = m

yanalaym [24]

Answer:

#1

${ \tt{a - x = y}} \\ \\ { \boxed{ \tt{x = a - y}}}$

#2

${ \tt{m = k - x}} \\ \\ { \boxed{ \tt{x = k - m}}}$

#3

${ \tt{k - {t}^{2}x = m }} \\ { \tt{ {t}^{2} x = k - m}} \\ \\ { \boxed{ \tt{x = \frac{k - m}{ {t}^{2} } }}}$

4 0

2 years ago

Read 2 more answers