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3 years ago

In September, Jerry read for 2/5 of an hour every day for 20 days. How many

Mathematics

1 answer:

Effectus [21]3 years ago

7 0

Answer:

Step-by-step explanation:

- 2/5 of an hour is equal to 24 min

- 24 times 20 is 480 minuets during September

- 480 minuets is 8 hours

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4. What is the median in this set of numbers? 5, 1, 2, 8, 9*<br> Ο 5<br> οοοο

muminat

Answer:

Step-by-step explanation:

Arrange the numbers from smallest to largest

1,2,5,8,9

The middle number is the median

5 is the middle number

5 is the median

5 0

3 years ago

(-7)y + 8 + 15y - 14

Aleksandr [31]

8y-6( add the variables together then add 8 to negative 14

5 0

3 years ago

Read 2 more answers

1/2 to the power of 3

yawa3891 [41]

0.125 or 1/8
hopes it helps you

5 0

3 years ago

Find the limit, if it exists. (If an answer does not exist, enter DNE.) lim (x, y) → (0, 0) x4 − 34y2 x2 + 17y2

HACTEHA [7]

Answer:

Step-by-step explanation:

Given the limit of the function $\lim_{(x,y) \to (0,0)} \frac{x^4-34y^2}{x^2+17y^2}$ , to find the limit, the following steps must be taken.

Step 1: Substitute the limit at x = 0 and y = 0 into the function

$= \lim_{(x,y) \to (0,0)} \frac{x^4-34y^2}{x^2+17y^2}\\= \frac{0^4-34(0)^2}{0^2+17(0)^2}\\= \frac{0}{0} (indeterminate)$

Step 2: Substitute y = mx int o the function and simplify

$= \lim_{(x,mx) \to (0,0)} \frac{x^4-34(mx)^2}{x^2+17(mx)^2}\\\\= \lim_{(x,mx) \to (0,0)} \frac{x^4-34m^2x^2}{x^2+17m^2x^2}\\\\\\= \lim_{(x,mx) \to (0,0)} \frac{x^2(x^2-34m^2)}{x^2(1+17m^2)}\\\\\\= \lim_{(x,mx) \to (0,0)} \frac{x^2-34m^2}{1+17m^2}\\$

$= \frac{0^2-34m^2}{1+17m^2}\\\\= \frac{34m^2}{1+17m^2}\\\\$

<em>Since there are still variable 'm' in the resulting function, this shows that the limit of the function does not exist, Hence, the function DNE</em>

4 0

4 years ago

⚠️⚠️⚠️⚠️ANSWER ASAP!!! ⚠️⚠️⚠️⚠️

Anon25 [30]

Answer:

0.08

Step-by-step explanation:

5^-2 x 2

1/25 or 0.04 x2

0.04 x 2= 0.08 or 2/25.

3 0

3 years ago