X^n ×X^n=X^10
X^n+n=X^10
X^2n=X^10
2n=10
n=10÷2
n=5
I hope you understand
For this case we must algebraically rewrite the given expression. So:
x: It is the variable that represents an unknown number
"double a number" is represented as: 
"6 less than double a number" is represented as: 
So, the final expression is: 
If we want to rewrite the expression in an equivalent way, we take common factor 2:

Asnwer:

Equivalent expression: 
Dude wheres the question, you have to ask legistic questions this is a school website not a circus
Answer:
ANSWER
Step-by-step explanation: