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harkovskaia [24]
3 years ago
8

Find the sum of the arithmetic series given ai = 45, an = 85, and n = 5.

Mathematics
1 answer:
seraphim [82]3 years ago
5 0

Answer:

C. 325.

Step-by-step explanation:

The last term a5 = 85

a1 = 45

Sum of n terms = n/2 (a1 + l)

So here we have n = 5, a1 = 45 and the last term l = 85

= (5/2)(45 + 85)

= 5/2 * 130

= 325.

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The function f(x)=(x-5)^2 +2 is not one-to-one. Identify a restricted domain that makes the function one-to-one, and find the in
Anon25 [30]

We have been given a quadratic function f(x)=(x-5)^{2} +2 and we need to restrict the domain such that it becomes a one to one function.

We know that vertex of this quadratic function occurs at (5,2).

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If we restrict the domain of this function to either (-\infty,5] or [5,\infty), it will become one to one function.

Let us know find its inverse.

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Upon interchanging x and y, we get:

x=(y-5)^{2}+2

Let us now solve this function for y.

(y-5)^{2}=x-2\\
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8 0
3 years ago
Kumar bought some mangoes. The price of each mango () is found to be 6 more than the total number of mangoes bought by him and t
spayn [35]

Answer:

Price = 20, Amount = 14

Step-by-step explanation:

A = Amount of Mangoes

P = Price for 1 Mango

P = A + 6

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insert A+6 for P

280 = (A+6) * A

280 = 6A + A²

280=1*a^2+6*a  | Vertausche beide Seiten der Gleichung.

1*a^2+6*a=280  | quadratische Ergänzung: ergänze auf beiden Seiten (3)^2

1*a^2+6*a+(3)^2=3^2+280  | Rechne 3 hoch 2 aus.

1*a^2+6*a+(3)^2=9+280  | addiere 9 und 280

1*a^2+6*a+(3)^2=9+280  | Fasse die rechte Seite mit Hilfe der binomischen Formel zusammen.

1*(1*a+(3))^2=289  | Auf beiden Seiten Quadratwurzel ziehen.

1*a+(3)=+-*289^0.5  

1*a_1+(3)=289^0.5  

1*a_1+3=289^0.5  | Ziehe die Wurzel aus 289

1*a_1+3=17  | -3

1*a_1=14  

8 0
3 years ago
The relationship between the number of pounds (lb) of peanuts and the price
lapo4ka [179]
Most likely B because one pound is equal to 6 dollars. So i think it would be x= 1 and y= 6

So put the x as the dom and 6 as the num?
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