Answer:
I believe the answer is 162 per season is the unit rate , I am really sorry if I am wrong.
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Good morning,</h2>
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<em><u>Answer</u></em>:
a+a+a = 3a.
4b-b = 3b.
3x²+x² = 4x².
<u><em>explanation</em></u>
a+a+a = 3a.
4b-b = b(4 - 1) = b × 3 = 3b.
3x²+x² = x²(3 + 1) = x² × 4 = 4x².
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:)
Let

be the point on the ground to with the 18 foot guy is anchored and

the point on the ground to with the 21 foot guy is anchored.
We can conclude that the <span>the two wires at the points where they are anchored are
21 feet apart. Check the procedures in the picture attached.</span>
Let A represent the amount Ann contributed, Z represent Zoe's contribution, and J represent Jim's contribution toward the present.
Ann (A): A
Zoe (Z): A = Z - 12 → Z = 12 + A
Jim (J): A = J - 16 → J = 16 + A
A + Z + J = 154
(A) + (12 + A) + (16 + A) = 154
3A + 28 = 154
3A = 126
A = 42
Ann (A): A = 42
Zoe (Z): Z = 12 + A = 12 + 42 = 54
Jim (J): J = 16 + A = 16 + 42 = 58
Answer: Ann=42, Zoe=54, Jim=58
Answer:
Step-by-step explanation
Let's say d = distance, r = speed and t = time
We know the distance formula is :
distance = speed x time
d = r multiplied by t
d = rt
If the speed is 15km/hr, the time would be 30 minutes shorter.
Since d = rt,
90 = 15t
t = 6,
This means the time taken for the bus to complete the journey at 15km/hr would be 6hrs.
Originally though, the journey takes 30 minutes longer.
So we can say t = 6.5 hrs , and we know d = 90
Now we use the distance formula:
d = rt, since we want to find the original speed, we want to find r.
Speed = distance/time
r = d/t
r = 90/6.5
r = 180/13
Therefore the original speed is 180/13 km/hr