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3 years ago

15

What is the correct radical form of this expression? (32a^10b^5/2)^2/5

1 answer:

spayn [35]3 years ago

8 0

The answer is choice A and here's why

The 2/5 outer most exponent means that we can break it down into 2*(1/5). The 2 is going to apply as an exponent for the whole parenthesis group. The 1/5 indicates we have a 5th root (similar to a square root or cube root,but instead of 2 or 3, it's 5)

In essence, I'm saying that $\LARGE x^{m/n} = \sqrt[n]{x^m}$

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How do I factor this? <br> 5x^2y+45x^3y^2

ruslelena [56]

Answer:

5 x^2 y (9 x y + 1)

Step-by-step explanation:

Factor the following:

45 x^3 y^2 + 5 x^2 y

Factor common terms out of 45 x^3 y^2 + 5 x^2 y.

Factor 5 x^2 y out of 45 x^3 y^2 + 5 x^2 y:

Answer: 5 x^2 y (9 x y + 1)

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2 years ago

Which symbol makes the number sentence true? -3.5__ 14/4 (< = >)

8090 [49]

Answer:

it's =

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8 0

3 years ago

Please help me out :P

Veseljchak [2.6K]

cos θ = $\frac{-4\sqrt{65} }{65}$ , sin θ = $\frac{-7\sqrt{65} }{65}$ , cot θ = 4/7, sec θ = $\frac{-\sqrt{65} }{4}$ , cosec θ = $\frac{-\sqrt{65} }{7}$

<h3>What are trigonometric ratios?</h3>

Trigonometric Ratios are values of all the trigonometric functions based on the value of the ratio of sides in a right-angled triangle.

Sin θ: Opposite Side to θ/Hypotenuse

Tan θ: Opposite Side/Adjacent Side & Sin θ/Cos

Cos θ: Adjacent Side to θ/Hypotenuse

Sec θ: Hypotenuse/Adjacent Side & 1/cos θ

Analysis:

tan θ = opposite/adjacent = 7/4

opposite = 7, adjacent = 4.

we now look for the hypotenuse of the right angled triangle

hypotenuse = $\sqrt{7^{2} + 4^{2} }$ = $\sqrt{49+16}$ = $\sqrt{65}$

sin θ = opposite/ hyp = $\frac{7}{\sqrt{65} }$

Rationalize, $\frac{7}{\sqrt{65} }$ x $\frac{\sqrt{65} }{\sqrt{65} }$ = $\frac{7\sqrt{65} }{65}$

But θ is in the third quadrant(180 - 270) and in the third quadrant only tan and cot are positive others are negative.

Therefore, sin θ = - $\frac{7\sqrt{65} }{65}$

cos θ = adj/hyp = $\frac{4}{\sqrt{65} }$

By rationalizing and knowing that cos θ is negative, cos θ = - $\frac{-4\sqrt{65} }{65}$

cot θ = 1/tan θ = 1/7/4 = 4/7

sec θ = 1/cos θ = 1/ $\frac{4}{\sqrt{65} }$ = - $\frac{-\sqrt{65} }{4}$

cosec θ = 1/sin θ = 1/ $\frac{\sqrt{65} }{7}$ = $\frac{-\sqrt{65} }{7}$

Learn more about trigonometric ratios: brainly.com/question/24349828

#SPJ1

5 0

2 years ago

17 Number of CD. Produced 100 3000 Number of CDs EXO HORO 1 M Nonth November Sentember July h The scatter plot shows the number

kobusy [5.1K]

Answer:

july

Step-by-step explanation:

id say its july but i cant see all the options so im not sure thats one of them!

4 0

3 years ago

Let h(x) = x*2 + kw - 8. If h(-1) = -5, what is the value of h(4)?<br> Help

Alisiya [41]

Answer:

h(4) = 0

Step-by-step explanation:

Hoping its ' kx '

$h(x) = x^2 + kx -8 \\\\h(-1) = (-1)^2 + k(-1) - 8\\\\-5 = 1 - k -8\\\\-5 = -k -7\\\\-5 + 7 = -k\\\\2 = -k\\-2 = k$

Now we have k = -2. We will find h(4).

$h(4) = (4)^2 + (-2)(4) - 8 = 16 -8 - 8 = 0$

4 0

3 years ago

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