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jek_recluse [69]
3 years ago
11

Find an equation for the perpendicular bisector of the line segment whose endpoints are (-1,5) and (7,9).​

Mathematics
2 answers:
harkovskaia [24]3 years ago
6 0

Answer:

say where we meet ❤️

PolarNik [594]3 years ago
3 0
Answer is x-2y+11=0 or 2y-x-11=0

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What is the difference between 6 2/4 and 1/6????? PLEASE HELP ME
VashaNatasha [74]

Answer:

6 2/4 is a mixed fraction and 1/6 is not.

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
Which line shows theINITIAL error in volume work?
aliina [53]

In step 2, V = \frac{4}{3}(3.14)(37.5) show the error in volume work.

Solution:

Given data:

The steps shows it is sphere.

Radius of the sphere = 12.5

The value of π = 3.14

Volume of the sphere = \frac{4}{3} \pi r^3

Step 1:

$V=\frac{4}{3} (3.14)(12.5)^3

$V=\frac{4}{3} (3.14)(12.5)(12.5)(12.5)

Step 2:

$V=\frac{4}{3} (3.14)(1953.125)

Step 3:

$V=\frac{4}{3} (6132.81)

Step 4:

V = 8177.08 cubic units

This is the correct solution.

But in the given options, in step 2, 12.5 is multiplied by 3.

That is not the correct step. You have to do 12.5 × 12.5 × 12.5.

Hence in step 2, V = \frac{4}{3}(3.14)(37.5) show the error in volume work.

7 0
3 years ago
The population of a small town in Alabama is 382 people. If the growth rate is 0.7%, what will its population be in 30 years?
goldenfox [79]
Formula for growth:

y = initial • (percent growth + 1)^time/frequency of growth

So, since initial population is 382

Percent growth is 0.007

The time is 30 years

And it goes it by .07% every 1 year,

y = 382 • (1.007)^30/1

y= 470.9203732 people

Since we can’t have 0.9 of a person, the population after 30 years will be 470 people.



4 0
2 years ago
Y=arccos(1/x)<br><br> Please help me do them all! I don’t know derivatives :(
Stells [14]

Answer:

f(x) =  {sec}^{ - 1} x \\ let \: y = {sec}^{ - 1} x  \rightarrow \: x = sec \: y\\  \frac{dx}{dx}  =  \frac{d(sec \: y)}{dx}  \\ 1 = \frac{d(sec \: y)}{dx} \times  \frac{dy}{dy}  \\ 1 = \frac{d(sec \: y)}{dy} \times  \frac{dy}{dx}  \\1 = tan \: y.sec \: y. \frac{dy}{dx}  \\ \frac{dy}{dx} =  \frac{1}{tan \: y.sec \: y}  \\ \frac{dy}{dx} =  \frac{1}{ \sqrt{( {sec}^{2}   \: y - 1}) .sec \: y}  \\ \frac{dy}{dx} =  \frac{1}{ |x |  \sqrt{ {x }^{2}  - 1} } \\   \therefore  \frac{d( {sec}^{ - 1}x) }{dx}  =  \frac{1}{ |x |  \sqrt{ {x }^{2}  - 1} } \\ \frac{d( {sec}^{ - 1}5x) }{dx}  =  \frac{1}{ |5x |  \sqrt{25 {x }^{2}  - 1} }\\\\y=arccos(\frac{1}{x})\Rightarrow cosy=\frac{1}{x}\\x=secy\Rightarrow y=arcsecx\\\therefore \frac{d( {sec}^{ - 1}x) }{dx}  =  \frac{1}{ |x |  \sqrt{ {x }^{2}  - 1} }

4 0
2 years ago
24xy-10y-18x from 13xy+12y+14x with explanation
Sav [38]

Answer:

24xy+2y−234x​2fromy+14x

Step-by-step explanation:

24xy−10y−(18×13)xxfromy+12y+14x

24xy−10y−234xxfromy+12y+14x

24xy−10y−234x​2fromy+12y+14x

24xy+(−10y+12y)−234x​2fromy+14x

4 0
3 years ago
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