Which triangle side lengths form a right triangle? Choose all that apply.

An equation is shown below: 6(2x – 11) + 15 = 3x + 12 Part A: Write the steps you will use to solve the equation, and explain ea

Aleks04 [339]

1.) you would distribute the 6---- 12x-66+15
2.) you would add like terms---- 12x-51=3x+12
3.) you would subtract 3x from each side of the equal sign---- 9x-51=12
4.) you would add 51 on each side of the equal sign----9x=63
5.) you would divide both sides of the equal sign by 9 giving you you answer--------- x=7

6 0

3 years ago

Read 2 more answers

Here is a data set: 5 10 10 10 15 100 after studying the data, the research realized that the value 100 was meant to be recorded

attashe74 [19]

Answer:

The mean and SD will change

The median is a better measure of the center since it will not change in this case

Step-by-step explanation:

Given that the value 100 was changed to 15, what will happen is that the value of the mean will decrease since there is a lower total value now. This will consequently decrease the value of the standard deviation too.

Yes, the median will be a better choice

This is because, by changing the value of 100 to 15, the value of the median stays the same and thus the previous information would not be changed if the median we used .

5 0

3 years ago

The diagonal of a TV is 26 inches long. Assuming that this diagonal forms a pair of 30-60-90 right triangles, what are the exact

Tema [17]

Hello,
let's assume a the width, b the heigth.

sin 30°=a/26=1/2==>a=26/2=13 (in)
cos 30°=b/26=√3/2==>b=26*√3 / 2=13√3≈22.51666.... (in)

4 0

3 years ago

Two students in your class, Hunter and Maggie, are disputing a function. Hunter says that for the function, between x = -2 and x

kirill115 [55]

They can both be correct because if 0 is the turning point their answers are the same

5 0

3 years ago

Let C(t) be the concentration of a drug in the bloodstream. As the body eliminates the drug, C(t) decreases at a rate that is pr

tia_tia [17]

Answer:

See explanation below

Step-by-step explanation:

In this case, let's answer this by parts:

<u>a) Concentration at time t when Co is concentration at t = 0:</u>

In this case, we will use the initial expression but without the 2, so:

C(t) = -kC

In this case, we want to know the concentration at time t so:

C'(t) = -kC(t) derivating:

dC/dt = -kC

dC/C = -kdt From here, we can do integrals so:

lnC = -kt + C₁ (1)

Now, it's time to replace t = 0 and C = C₀:

lnC₀ = -k(0) + C₁

lnC₀ = C₁ (2)

Replacing (2) in (1) we have:

lnC = -kt + lnC₀

lnC - lnC₀ = -kt

ln(C/C₀) = -kt

C/C₀ = e^(-kt)

C(t) = C₀ e^(-kt) (3)

This is the expression for C at given time t.

<u>2. time to eliminate 80% of the drug:</u>

With the first data, we need to calculate the value of k, which will be constant at any given time so:

C(t) = C₀ e^(-kt)

0.5C₀ = C₀ e^(-30k)

0.5 = e^(-30k)

ln(0.5) = -30k

k = 0.02310

Now with this value we can calculate the time to eliminate 80% of the drug or simply in other words, that we just have a remaining of 0.2C₀:

0.2C₀ = C₀ e^(-0.0231t)

ln(0.2) = -0.0231t

-ln(0.2) / 0.0231 = t

t = 69.67 h

This is the time to eliminate 80% of the drug

8 0

3 years ago