Multiply both sides of the fraction by 3.
3/4 = 9/12
All you've got to do is some simple algebra! When you solve for a variable, you are trying to get it alone on one side of the equation. So, we want something that looks like y = ...
First, add 21x to both sides of the equation. This will cancel out the -21x on the left side.
-21x + 3y = 6
-21x + 3y + 21x = 6 + 21x
3y = 21x + 6
Now, to get y alone, divide both sides of the equation by 3. This will cancel out the coefficient of 3 on the left side.
3y = 21x + 6
(3y)/3 = (21x + 6)/3
y = 7x + 2
There's the answer. Hope that helps! :)
Fun. I prefer Oxymetazoline.
For the control group we have a headache probability of
c = 368/1671 = .220
For the experimental group we have a headache probability of
e = 494/2013 = .245
The observed difference is
d = e - c = .025
The variance of the difference is
s² = c(1-c)/n₁ + e(1-e)/n₂
so the standard deviation is
We get a t statistic on the difference of
t = d/s = .025/.0139 = 1.79
We're interested in the one sided test, P(d > 0). We have enough dfs to assume normality. We look up in the standard normal table
P(z < 1.79) = .96327
so
p = P(z > 1.79) = 1 - .96327 = 0.037 = 3.7%
Answer: That's less that 10% so we have evidence to conclude that headaches are significantly greater in the experimental group.
Lol I was looking for help for this question but I couldn't find it so I had to figure it out my self and the answer is 40
Answer:
(A) OE
Step-by-step explanation:
From the given figure, it can be seen that TG and LI are the chords of the circle with center O such that TG=LI=10.4 which means that TG is congruent to LI.
Also, OE and OH gives the shortest distance(perpendicular) of the chord LI and TG respectively from center of circle O.
And, We know that "the congruent chords are equidistant from the center of a circle."
Therefore, we can conclude that, OH is congruent to OE.
Hence, option (A) is correct.
