The system reads:
8x-3y=13
-3x-8y=-14
Solve this by solving for one variable at a time by cancelling the other. We will begin by solving for y and cancelling x. To do this, you need to find the least common multiple (LCM) of the x variables and multiply both equations by the number which will make them equal the LCM. For 8 and 3, the LCM is 24, so you will multiply the top equation by 3 and the bottom one by 8.
<em>*****In order for the variables to cancel, the signs need to be opposite. In this system, one is already positive and the other negative; if this were not the case, one of the equations would have needed to be multiplied by a negative number.*****</em>
The system becomes:
24x-9y=39
-24x-24y=42
Now, you can combine the equations by adding them:
-33y=81
Solve for y:
<em>*Divide both sides by -33*</em>
y=27/11
To find x, you can select one of the given equations, plug in 27/11 for y, and solve for x. We'll use the first equation:
8x-3(27/11)=13
8x-81/11=13
<em>*Add 81/11 to both sides*</em>
8x=224/11
<em>*Divide both sides by 8*</em>
x=28/11
Hope this helps!!
The point of the y-coordinate would drop down below the x-axis.
Answer:
A
Step-by-step explanation:
Answer:
for a) the following answers are in order from left to right.
5, 2, 2, and 10
for b) this is the square root of three: 1.73205080757 [u can round it to the first decimal place urself! :)]
Step-by-step explanation:
b) 4 = x^2 + 1
4 - 1 = x^2 - 1
3 = x^2
so the sqaure root for 3 is 1.73205080757
4 / 5 - 2 / 3 ( taking LCM on bottom )
= ( 12 - 10 ) / 15
= 2 / 15 Ans
