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Fantom [35]
3 years ago
15

A recent drug survey showed an increase in use of drugs and alcohol among local high school students as compared to the national

percent. Suppose that a survey of 100 local youths and 100 national youths is conducted to see if the percentage of drug and alcohol use is higher locally than nationally. Locally, 65 seniors reported using drugs or alcohol within the past month, while 61 national seniors reported using them.
Required:
Conduct a hypothesis test at the 5% level.
Mathematics
1 answer:
GaryK [48]3 years ago
4 0

Answer:

We fail to reject H0

Step-by-step explanation:

Null hypothesis : H0 : Plocal ≤ Pnational

Alternative hypothesis : H1 : Plocal > Pnational

Plocal = P1 = 65/100 = 0.65

Pnational = P2 = 61/100 = 0.61

n1 = 100 ; n2 = 100

Mean, m = P1 - P2 = 0.65 - 0.61 = 0.04

The standard deviation : = sqrt(Variance)

Variance = P1(1 - P1) /n1 + P2(1 - P2) /n2

Variance = 0.65(0.35)/100 + 0.61(0.39)/100

Variance = 0.002275 + 0.002379 = 0.004654

Standard deviation (s) = √(0.004654) = 0.06822

Z = m/s = 0.04 / 0.06822 = 0.586

Using the p-value from Z score calculator :

Hence, Pvalue for a Zscore 0.586 at 5% = 0.278938

Since ;

P-value is > α ; 0.278938 > 0.05

Then we fail to reject H0

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Let us suppose we have data on the absorbency of paper towels that were produced by two different manufacturing processes. From
maksim [4K]

Answer:

The 95% CI for the difference of means is:

-155.45 \leq \mu_1-\mu_2 \leq -44.55

Step-by-step explanation:

<em>The question is incomplete:</em>

<em>"Find a 95% confidence interval on the difference of the towels mean absorbency produced by the two processes. Assumed that the standard deviations are estimated from the data. Round to two decimals places."</em>

Process 1:

- Sample size: 10

- Mean: 200

- S.D.: 15

Process 2:

- Sample size:  4

- Mean: 300

- S.D.: 50

The difference of the sample means is:

M_d=M_1-M_2=200-300=-100

The standard deviation can be estimated as:

\sigma_d=\sqrt{\frac{\sigma_1^2}{n_1}+\frac{\sigma_2^2}{n_2}}\\\\\sigma_d=\sqrt{\frac{15^2}{10}+\frac{50^2}{4}} =\sqrt{22.5+625}=\sqrt{647.5}=25.45

The degrees of freedom are:

df=n_1+n_2-2=10+4-2=12

The t-value for a 95% confidence interval and 12 degrees of freedom is t=±2.179.

Then, the confidence interval can be written as:

M_d-t\cdot \sigma_d\leq \mu_1-\mu_2 \leq M_d+t\cdot \sigma_d\\\\-100-2.179*25.45\leq \mu_1-\mu_2 \leq -100+2.179*25.45\\\\-100-55.45 \leq \mu_1-\mu_2 \leq -100+55.45\\\\ -155.45 \leq \mu_1-\mu_2 \leq -44.55

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Step-by-step explanation:

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Read 2 more answers
8x+3y= 28 and 7x-3y=2<br>solve for x and y simontaniasly using elimination ​
EleoNora [17]

Answer:

x=2, y=4

Step-by-step explanation:

When using elimination, the objective is to elimate one variable. In this case, we see that "y" can easily be eliminated by adding the two equations together since you will get 3y + (-3y) which will eliminate y because the value would become 0, letting us solve for x.

\left \{ {{8x+3y=28} \atop {7x-3y=2}} \right. +\\

Then we get

15x =30, because the y's will eliminated, and 8x+7x is 15x, and 28+2 is 30.

Then divide by 15 on both sides and you get x=2

If x=2, then we can substitute that value into any of the previous given equations and find the value of y.

8×2 +3y = 28

16+3y=28

3y=12

y=4

So the answer to your system of equations would be x=2, and y=4

You can substitute the answers we found to see that they satisfy the equation.

Hope this helped.

6 0
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