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Bad White [126]
3 years ago
14

12x=11x+6 How do I solve this, it’s proving lines parallel

Mathematics
1 answer:
Alex3 years ago
4 0
It would be helpful to see a picture, but if you are just trying to solve for X. The answer would be 6.
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Find the area of the figure . Sides meet at right angles .
AlexFokin [52]

Answer:

49,152

Step-by-step explanation:

top side=12ft

5 bottom sides=4ft each

2 L,R sides=2ft each

= 12×4×4×4×4×4×2×2

= 49,152

3 0
3 years ago
Read 2 more answers
PLEASE ANSWER ASASSP!!!!!!!!!!!!!!!!!!!!<br> Sovle the equation<br> 6 (y + 1.5) = -18<br> What is y?
Ede4ka [16]

Answer:

6(y+1.5)=-18

6y+9=-18 -9

6y=-27 ÷6

y=-4.5

Step-by-step explanation:

prove me wrong

7 0
3 years ago
Read 2 more answers
What is the area of this triangle
Misha Larkins [42]

Answer:

Probably b or e

Step-by-step explanation:

this took me a while to answer this.

4 0
3 years ago
Consider the following differential equation. x^2y' + xy = 3 (a) Show that every member of the family of functions y = (3ln(x) +
Veronika [31]

Answer:

Verified

y(x) = \frac{3Ln(x) + 3}{x}

y(x) = \frac{3Ln(x) + 3 - 3Ln(3)}{x}

Step-by-step explanation:

Question:-

- We are given the following non-homogeneous ODE as follows:

                           x^2y' +xy = 3

- A general solution to the above ODE is also given as:

                          y = \frac{3Ln(x) + C  }{x}

- We are to prove that every member of the family of curves defined by the above given function ( y ) is indeed a solution to the given ODE.

Solution:-

- To determine the validity of the solution we will first compute the first derivative of the given function ( y ) as follows. Apply the quotient rule.

                          y' = \frac{\frac{d}{dx}( 3Ln(x) + C ) . x - ( 3Ln(x) + C ) . \frac{d}{dx} (x)  }{x^2} \\\\y' = \frac{\frac{3}{x}.x - ( 3Ln(x) + C ).(1)}{x^2} \\\\y' = - \frac{3Ln(x) + C - 3}{x^2}

- Now we will plug in the evaluated first derivative ( y' ) and function ( y ) into the given ODE and prove that right hand side is equal to the left hand side of the equality as follows:

                          -\frac{3Ln(x) + C - 3}{x^2}.x^2 + \frac{3Ln(x) + C}{x}.x = 3\\\\-3Ln(x) - C + 3 + 3Ln(x) + C= 3\\\\3 = 3

- The equality holds true for all values of " C "; hence, the function ( y ) is the general solution to the given ODE.

- To determine the complete solution subjected to the initial conditions y (1) = 3. We would need the evaluate the value of constant ( C ) such that the solution ( y ) is satisfied as follows:

                         y( 1 ) = \frac{3Ln(1) + C }{1} = 3\\\\0 + C = 3, C = 3

- Therefore, the complete solution to the given ODE can be expressed as:

                        y ( x ) = \frac{3Ln(x) + 3 }{x}

- To determine the complete solution subjected to the initial conditions y (3) = 1. We would need the evaluate the value of constant ( C ) such that the solution ( y ) is satisfied as follows:

                         y(3) = \frac{3Ln(3) + C}{3} = 1\\\\y(3) = 3Ln(3) + C = 3\\\\C = 3 - 3Ln(3)

- Therefore, the complete solution to the given ODE can be expressed as:

                        y(x) = \frac{3Ln(x) + 3 - 3Ln(3)}{y}

                           

Download docx
6 0
3 years ago
What is the simplified expression for the expression below? 4(3x – 2) + 6x(2 – 1)
igor_vitrenko [27]

Step-by-step explanation:

4(3x-2) + 6x(2-1)

10x + 11x

21x

8 0
4 years ago
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