267.05 hope this helpssss
Answer: multiply x by 2 in the first equation and subtract the second equation
Step-by-step explanation:
To solve a system of linear equations by elimination method , our first step is to make its (either x or y) coefficient same.
For that we multiply a number to both sides of the equation not to only one term.
So by checking all the given options it is pretty clear that the last option is not applicable for elimination method because in this 2 is multiplied to only one term, which proceeds to loose the balance of the equation.
Thus , an INCORRECT step that will NOT produce a system with the same solution is "multiply x by 2 in the first equation and subtract the second equation
".
Answer:
B
Step-by-step explanation:
+ 6 = x ( subtract 6 from both sides )
= x - 6 ( square both sides )
x = (x - 6)² ← expand using FOIL
x = x² - 12x + 36 ( subtract x from both sides )
0 = x² - 13x + 36 , that is
x² - 13x + 36 = 0 ← in standard form
(x - 4)(x - 9) = 0 ← in factored form
Equate each factor to zero and solve for x
x - 4 = 0 ⇒ x = 4
x - 9 = 0 ⇒ x = 9
As a check
Substitute these values into the equation and if both sides are equal then they are the solutions.
x = 4
left side =
+ 6 = 2 + 6 = 8
right side = x = 4
Since 8 ≠ 4 then x = 4 is an extraneous solution
x = 9
left side =
+ 6 = 3 + 6 = 9
right side = x = 9
Thus the solution is x = 9 → B
A, c, and d
plug in each x in the equation and it should equal the y value
Answer:
- Question 1a. i)

- Question 1a. ii)

- Question 1b)

Explanation:
<u><em>Question 1 a. i) Find the value of x.</em></u>

For the smalll triangle you can write:

For tthe big triangle:

Substitute:

Solve for x:

<u><em>Question 1a ii) Find the volume of the frustrum</em></u>
- Find the volume of a cone with height = 2.7m + 1.8m = 4.5m, and radius = 2.5m
Formula:

Substitute:

- Find the volume of a cone with heigth = 1.8m and radius = 1m

- Subtract the volume of the small cone from the volume of the big cone

<u><em>Question 1b. Calculate the volume of the bin</em></u>
<u>i) Upper frustrum</u>
This is the same frustrum from the equation of above, thus ist volume is 27.6m³.
<u>ii) Lower frustrum</u>




<u>iii) Add the volume of the two frustrums</u>