Create two different expressions that are equivalent to 10(8k + k). Please help

Mathematics

2 answers:

dimulka [17.4K]3 years ago

8 0

So 10 times 8 equals 80k +10k

nekit [7.7K]3 years ago

6 0

Step-by-step explanation:hope that helps

Given: 10(8k + k)=80k+10k=90k

THE TWO EXPRESSION THAT ARE EQUIVALENT 10(8k + k).

1. -10(-8k + -k) = 80k+10k=90k

2. 1(80k+10k) = 80k+10k= 90k

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$\large\boxed{\theta=-\dfrac{\pi}{4}+k\pi\ or\ \theta=k\pi}\ for\ k\in\mathbb{Z}$

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$\tan^2\theta+\tan\theta=0\\\\\tan\theta(\tan\theta+1)=0\iff\tan\theta=0\ \vee\ \tan\theta+1=0\\\\\tan\theta=0\Rightarrow \theta=k\pi\ \text{for}\ k\in\mathbb{Z}\\\\\tan\theta+1=0\qquad\text{subtract 1 from both sides}\\\\\tan\theta=-1\Rightarrow\theta=-\dfrac{\pi}{4}+k\pi\ \text{for}\ k\in\mathbb{Z}$