The value of y in the code segment is 444
<h3>How to determine the value of y?</h3>
The code segment is given as:
y = int(3 * '4')
Evaluate the expression in the bracket
y =int('444')
Remove the bracket
y = 444
Hence, the value of y in the code segment is 444
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X = first venture, y = second venture, z = third venture
x + y + z = 15,000
x + z = y + 7000
3x + 2y + 2z = 39,000
these are ur equations.....
x + y + z = 15,000
x - y + z = 7000
--------------------add
2x + 2z = 22,000
x + y + z = 15,000....multiply by -2
3x + 2y + 2z = 39,000
-------------------
-2x - 2y - 2z = - 30,000 (result of multiplying by -2)
3x + 2y + 2z = 39,000
------------------add
x = 9,000
2x + 2z = 22,000
2(9000) + 2z = 22000
18,000 + 2z = 22000
2z = 22000 - 18000
2z = 4000
z = 4000/2
z = 2,000
x + y + z = 15,000
9000 + y + 2000 = 15,000
11,000 + y = 15,000
y = 15,000 - 11,000
y = 4,000
first venture (x) = 9,000 <==
second venture (y) = 4,000 <==
third venture (z) = 2,000 <==
Answer:
Graph C with the green dots.
Step-by-step explanation:
y = 0.5x + 5 is a linear equation, so we can rule out A because it is not straight.
5 represents the y-intercept, so we rule out B because that graph doesn't intercept the y-axis at (0,5).
Graph C represents a straight line that passes through (0, 5) & has a 0.5 slope, so that is our answer.
Hope this helps. :0)
Answer:
Step-by-step explanation:
Since it is a regular hexagon, the length of its sides are equal. And same as the distance across its flats.
So that;
NR ≅ OP (property of a regular polygon)
PM ≅ RM (half of the distance across flats of a polygon)
NM ≅ OM (half of the distance across flats of a polygon)
<NMR ≅ <PMO (vertically opposite angles)
<NRM ≅ <OPM (alternate angle property)
<RNM ≅ <POM (alternate angle property)
This therefore proves that: ΔNRM = ΔOPM
