Using the information given above, the sampling distribution of the sample proportion of 100-ohm gold-band is 2.
- <em>Sampling distribution of proportion, P = 2% = 0.02 </em>
- <em>Sample size, n = 100</em>
<u>The sampling distribution of the sample proportion can be calculated thus</u>:
- <em>Distribution of sample proportion = np</em>
Distribution of sample proportion = (100 × 0.02) = 2
Therefore, there is a probability that only 2 of the samples will have resistances exceeding 105 ohms.
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Answer:
D. 16 ft
Step-by-step explanation:
h = √20² - (24/2)² = √400-144 = √256 = 16
The answer is 3 at least thats what ive learned
First, find your total sales. You do this by adding all the sales together, 2030+1540+1800=5370. Now, for each person, divide their sales by total sales.Lola) 2030/5370=203/537≈0.378=37.8%Ahmed) 1540/5370=154/537≈0.287=28.7%Tommy) 1800/5370=180/537=60/179≈0.335=33.5%