Since there are more parakeets than canaries, it is not possible to have only 1 of each bird in each cage <u>and</u> have the same number of birds in each cage.
He could use 42 cages, putting a canary in with the parakeet in 18 of them. Then he would have 18 cages with 2 birds each, and 24 cages with 1 bird each.
The only way to have the same number of birds (1) in all cages is to have 60 cages, 42 of which have 1 parakeet, and 18 of which have 1 canary.
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If more than 1 of each kind of bird can be put in the cage, the collection of birds could be put into 6 cages, each of which would be home to 7 parakeets and 3 canaries.
Answer:
The number of different 7 card hands possibility is 133784560
Step-by-step explanation:
The computation of the number of different 7 card hands possibility is shown below:
Here we use the combination as the orders of choosing it is not significant
So,
The number of the different hands possible would be
= 
= 52! ÷ (7! × (52 - 7)!)
= 133784560
Hence, the number of different 7 card hands possibility is 133784560
5.6 is a mixed fraction is...
5.6= 5 3/5
Answer:
The answer for f(2) is 11.
Step-by-step explanation:
f(x) = 3x2 + 2x - 5
f(2) = 3(2)2 + 2(2) - 5
f(2) = 6(2) + 4 - 5
f(2) = 12 + 4 - 5
f(2) = 16 - 5
f(2) = 11
4 times n=-48
4n=-48
that is the translateion
