J has coordinates of (10,-2) and N has coordinates of (-4,6) find the midpoints of JN
2 answers:
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Answer:
n = 8
Step-by-step explanation:
Continuing the sequence using
+
x₄ = x₂ + x₃ =1 + 2 = 3
x₅ = x₃ + x₄ = 2 + 3 = 5
x₆ = x₄ + x₅ = 3 + 5 = 8
x₇ = x₅ + x₆ = 5 + 8 = 13
x₈ = x₆ + x₇ = 8 + 13 = 21
x₉ = x₇ + x₈ = 13 + 21 = 34
x₁₀ = x₈ + x₉ = 21 + 34 = 55 ← with n = 8
Answer:
11 ;
Step-by-step explanation:
Given the data:
30 27 22 25 24 25 24 15 35 35 33 52 49 10 27 18 20 23 24 25 30 24 24 24 18 20 25 27 24 32 13 13 21 2 37 35 32 33 29 3 28 28 25 29 31
Number of classes = 5
Class width : Range / number of classes
Class width = (maximum - minimum) / 5
Class width = (52 - 2) / 5 = 50/5 = 10 + 1 = 11
For the frequency table showing class limits, class boundaries, midpoints, frequencies, relative frequencies, and cumulative frequencies and histogram
Kindly check attached picture
