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ruslelena [56]
3 years ago
5

J has coordinates of (10,-2) and N has coordinates of (-4,6) find the midpoints of JN

Mathematics
2 answers:
meriva3 years ago
5 0
First Off Here is the midpoint Formula (Below Pic) 2nd, the Midpoint is located at (3, 2)

                    Hope this helped! Please Mark As Brainliest ;)



MissTica3 years ago
4 0
X coordinate for midpoint =(x1+x2)/2=(10-4)/2=6/2=3
y coordinate for midpoint =(y1+y2)/2=(-2+6)/2=4/2=2
Midpoint coordinates (3,2)
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</span></span></span></span> <span><span> 5x2-23x=-26</span> </span>Two solutions were found :<span><span>  x = 2 </span><span>  x = 13/5 = 2.600
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Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

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<span> Step  1  :</span><span>Equation at the end of step  1  :</span><span> (5x2 - 23x) - -26 = 0 </span><span> Step  2  :</span>Trying to factor by splitting the middle term

<span> 2.1 </span>    Factoring <span> 5x2-23x+26</span> 

The first term is, <span> <span>5x2</span> </span> its coefficient is <span> 5 </span>.
The middle term is, <span> -23x </span> its coefficient is <span> -23 </span>.
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Step-1 : Multiply the coefficient of the first term by the constant <span>  5 • 26 = 130</span> 

Step-2 : Find two factors of  130  whose sum equals the coefficient of the middle term, which is  <span> -23 </span>.

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</span> </span> <span>       -13    +    -10    =    -23    That's it</span></span>
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