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ruslelena [56]
3 years ago
5

J has coordinates of (10,-2) and N has coordinates of (-4,6) find the midpoints of JN

Mathematics
2 answers:
meriva3 years ago
5 0
First Off Here is the midpoint Formula (Below Pic) 2nd, the Midpoint is located at (3, 2)

                    Hope this helped! Please Mark As Brainliest ;)



MissTica3 years ago
4 0
X coordinate for midpoint =(x1+x2)/2=(10-4)/2=6/2=3
y coordinate for midpoint =(y1+y2)/2=(-2+6)/2=4/2=2
Midpoint coordinates (3,2)
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Unlike fiction, nonfiction does not embellish the stories to attract the readers' attention but tells the simple truth.

2. The denotative meaning of <u>"allayed"</u> in the above passage is <u>B. relieved.</u>

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8 0
2 years ago
(2 1/4) x (-8) distributive property
Paladinen [302]
I hope this helps you




[2×4+1/4]×(-8)



[8+1/4]×(-8)


9×-8/4


9×-2


-18




6 0
3 years ago
2 sqrt of 3 times 3 sqrt of 15
bixtya [17]
The answer would be 40.2 I'm pretty sure I'm right. I hope I helped!
5 0
3 years ago
Dan has a board that is 8 3/4 feet long. He cuts off 4 5/6 feet and says he has 4 1/12
Ilia_Sergeevich [38]

Answer:

C

Step-by-step explanation:

The answer to this problem is 3 11/12.

1.8 3/4= 8 9/12

2.4 5/6 = 4 10/12

if you minus the two numbers, you get 3 11/12.

3 0
3 years ago
Read 2 more answers
Find the product.<br><br> (-5a ^2)^3·a ^5<br><br> A)-15a10<br> B)-125a11<br> C)15a6<br> D)-125a10
Ber [7]

Answer:

  B)  -125a^11

Step-by-step explanation:

(-5a^2)^3·a^5 = (-5)^3·a^6·a^5

  = (-5)^3·a^(2·3)·a^5

  = (-5)^3·a^6·a^5

  = -125·a^(6+5)

  = -125·a^11 . . . . matches choice B

_____

The applicable rules of exponents are ...

  (a^b)(a^c) = a^(b+c)

  (a^b)^c = a^(bc)

5 0
3 years ago
Read 2 more answers
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