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3 years ago

J has coordinates of (10,-2) and N has coordinates of (-4,6) find the midpoints of JN

2 answers:

meriva3 years ago

5 0

First Off Here is the midpoint Formula (Below Pic) 2nd, the Midpoint is located at (3, 2)

Hope this helped! Please Mark As Brainliest ;)

MissTica3 years ago

4 0

X coordinate for midpoint =(x1+x2)/2=(10-4)/2=6/2=3
y coordinate for midpoint =(y1+y2)/2=(-2+6)/2=4/2=2
Midpoint coordinates (3,2)

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What is 9+m=1.5 i need the answer for m

Oksi-84 [34.3K]

Answer:

m = - 7.5

Step-by-step explanation:

Given

9 + m = 1.5 ( subtract 9 from both sides )

m = - 7.5

5 0

3 years ago

Evaluate the surface integral. s x2 + y2 + z2 ds s is the part of the cylinder x2 + y2 = 4 that lies between the planes z = 0 an

Leya [2.2K]

Parameterize the lateral face $T_1$ of the cylinder by

$\mathbf r_1(u,v)=(x(u,v),y(u,v),z(u,v))=(2\cos u,2\sin u,v$

where $0\le u\le2\pi$ and $0\le v\le3$ , and parameterize the disks $T_2,T_3$ as

$\mathbf r_2(r,\theta)=(x(r,\theta),y(r,\theta),z(r,\theta))=(r\cos\theta,r\sin\theta,0)$
$\mathbf r_3(r,\theta)=(r\cos\theta,r\sin\theta,3)$

where $0\le r\le2$ and $0\le\theta\le2\pi$ .

The integral along the surface of the cylinder (with outward/positive orientation) is then

$\displaystyle\iint_S(x^2+y^2+z^2)\,\mathrm dS=\left\{\iint_{T_1}+\iint_{T_2}+\iint_{T_3}\right\}(x^2+y^2+z^2)\,\mathrm dS$
$=\displaystyle\int_{u=0}^{u=2\pi}\int_{v=0}^{v=3}((2\cos u)^2+(2\sin u)^2+v^2)\left\|{{\mathbf r}_1}_u\times{{\mathbf r}_2}_v\right\|\,\mathrm dv\,\mathrm du+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}((r\cos\theta)^2+(r\sin\theta)^2+0^2)\left\|{{\mathbf r}_2}_r\times{{\mathbf r}_2}_\theta\right\|\,\mathrm d\theta\,\mathrm dr+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}((r\cos\theta)^2+(r\sin\theta)^2+3^2)\left\|{{\mathbf r}_3}_r\times{{\mathbf r}_3}_\theta\right\|\,\mathrm d\theta\,\mathrm dr$
$=\displaystyle2\int_{u=0}^{u=2\pi}\int_{v=0}^{v=3}(v^2+4)\,\mathrm dv\,\mathrm du+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}r^3\,\mathrm d\theta\,\mathrm dr+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}r(r^2+9)\,\mathrm d\theta\,\mathrm dr$
$=\displaystyle4\pi\int_{v=0}^{v=3}(v^2+4)\,\mathrm dv+2\pi\int_{r=0}^{r=2}r^3\,\mathrm dr+2\pi\int_{r=0}^{r=2}r(r^2+9)\,\mathrm dr$
$=136\pi$

7 0

3 years ago

42=3(2-3h) can someone plz answer and show me how to do this

maria [59]

You have to use distributive property.

4 0

3 years ago

The snack bar at your school has added sushi to its menu. The ingredients for one roll include sushi rice, seaweed sheets, cucum

soldi70 [24.7K]

The answer si:
- 16 servings - 6 oz of salmon
- 24 servings - 9 oz of salmon
- 80 servings - 30 oz of salmon
- 100 servings - 37.5 oz of salmon

1 roll is 8 servings and it is also made of 3oz of smoked salmon. That means that 3oz of smoked salmon is needed fo 8 servings.
Now, let's made some proportions:

16 servings:
3 oz is for 8 servings, how much oz is for 16 servings:
3 : 8 = x : 16
x = 3 · 16 ÷ 8 = 6 oz

24 servings:
3 oz is for 8 servings, how much oz is for 24 servings:
3 : 8 = x : 24
x = 3 · 24 ÷ 8 = 9 oz

80 servings:
3 oz is for 8 servings, how much oz is for 80 servings:
3 : 8 = x : 80
x = 3 · 80 ÷ 8 = 30 oz

100 servings:
3 oz is for 8 servings, how much oz is for 100 servings:
3 : 8 = x : 100
x = 3 · 100 ÷ 8 = 37.5 oz

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3 years ago

At the post office, 42% of packages ship priority mail. If 150 packages are shipped today, how many will not go priority mail?

kenny6666 [7]

Since 42% of packages are being shipped via priority mail, we can safely assume the other 58% are not. 150 x 0.58 is 87.

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3 years ago