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dolphi86 [110]
3 years ago
6

The front of an a-frame house is in the shape of a triangle.The height of the house is 20 feet.The area of the front of the a-fr

ame is 600 square feet.Write and solve an equation to find the base of the A-frame house
Mathematics
1 answer:
FinnZ [79.3K]3 years ago
4 0
So, you have a triangular a-frame. The height is 20 feet, and the area is 600 square feet. The area of a triangle is represented by this equation:

\frac{1}{2} *b*h

Where:
- b is the base length
- h is the height

So, basically just plug things in:

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Given that 2x + 1 =5, what is the value of (x+3)^3
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Answer: 125

Step-by-step explanation:

First, solve for x in the first equation.

1) Subtract 1 from both sides.

2x = 4

2) Divide by 2 on both sides.

x = 2

Next, substitute the value of x into the second expression.

(2 + 3)^3

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Find where the two lines intersect.Please help
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2 years ago
If p=(-3,-2) and q=(1,6) are the endpoints of the diameter of a circle find the equation of the circle
stira [4]

Answer:

<em>The equation of the circle   (x +1) )² +(y-(2))² = (2(√5))²</em>

<em>   or </em>

<em>The equation of the circle    x² + 2 x + y² - 4 y  = 15</em>

<u>Step-by-step explanation:</u>

Given points end  Points are p(-3,-2) and q( 1,6)

<em>The distance of two points formula</em>

P Q = \sqrt{x_{2} - x_{1})^{2} + ((y_{2} -y_{1})^{2}   }

P Q = \sqrt{1 - (-3)^{2} + ((6 -(-2))^{2}   }

P Q = \sqrt{16+64} = \sqrt{80}

<em>The diameter 'd' = 2 r</em>

                       2 r = √80

                            = \sqrt{16 X 5}

                           = 4 \sqrt{5}

                     <em> r =  2√5</em>

<em>Mid-point of two end points </em>

<em>                        </em>(\frac{x_{1} + x_{2} }{2} , \frac{y_{1} +y_{2} }{2} ) = (\frac{-3+1}{2} ,\frac{-2 +6}{2} )<em></em>

<em>                                               = (-1 ,2)</em>

<em>Mid-point of two end points = center of the circle</em>

<em>                                     (h,k) = (-1 , 2)</em>

                 

The equation of the circle

           (x -h )² +(y-k)² = r²

<em>          (x -(-1) )² +(y-(2))² = (2(√5))²</em>

<em>         x² + 2 x + 1 + y² - 4 y + 4 = 20</em>

<em>          x² + 2 x + y² - 4 y  = 20 -5</em>

<em>           x² + 2 x + y² - 4 y  = 15</em>

<u><em>Final answer</em></u><em>:-</em>

<em>The equation of the circle   (x +1) )² +(y-(2))² = (2(√5))²</em>

<em>   or </em>

<em>The equation of the circle    x² + 2 x + y² - 4 y  = 15</em>

<em>                  </em>

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3 years ago
Which numbers is a solution to x&gt;10
IceJOKER [234]

14 > 10 

all the numbers that bigger than 10 can replace x


6 0
2 years ago
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