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dolphi86 [110]
3 years ago
6

The front of an a-frame house is in the shape of a triangle.The height of the house is 20 feet.The area of the front of the a-fr

ame is 600 square feet.Write and solve an equation to find the base of the A-frame house
Mathematics
1 answer:
FinnZ [79.3K]3 years ago
4 0
So, you have a triangular a-frame. The height is 20 feet, and the area is 600 square feet. The area of a triangle is represented by this equation:

\frac{1}{2} *b*h

Where:
- b is the base length
- h is the height

So, basically just plug things in:

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Can someone help me with this question please
erastovalidia [21]

for 1st

use the formula of inlargement

A(x,y)when enlarging by scale factor k gives A'(kx,ky)

for 2nd

a=

(2a+3)-(a-5)(2a+2)+a^2

b=

3y(7y-8)

3 0
4 years ago
Litter such as leaves falls to the forest floor, where the action of insects and bacteria initiates the decay process. Let A be
Travka [436]

Answer:

D = L/k

Step-by-step explanation:

Since A represents the amount of litter present in grams per square meter as a function of time in years, the net rate of litter present is

dA/dt = in flow - out flow

Since litter falls at a constant rate of L  grams per square meter per year, in flow = L

Since litter decays at a constant proportional rate of k per year, the total amount of litter decay per square meter per year is A × k = Ak = out flow

So,

dA/dt = in flow - out flow

dA/dt = L - Ak

Separating the variables, we have

dA/(L - Ak) = dt

Integrating, we have

∫-kdA/-k(L - Ak) = ∫dt

1/k∫-kdA/(L - Ak) = ∫dt

1/k㏑(L - Ak) = t + C

㏑(L - Ak) = kt + kC

㏑(L - Ak) = kt + C'      (C' = kC)

taking exponents of both sides, we have

L - Ak = e^{kt + C'} \\L - Ak = e^{kt}e^{C'}\\L - Ak = C"e^{kt}      (C" = e^{C'} )\\Ak = L - C"e^{kt}\\A = \frac{L}{k}  - \frac{C"}{k} e^{kt}

When t = 0, A(0) = 0 (since the forest floor is initially clear)

A = \frac{L}{k}  - \frac{C"}{k} e^{kt}\\0 = \frac{L}{k}  - \frac{C"}{k} e^{k0}\\0 = \frac{L}{k}  - \frac{C"}{k} e^{0}\\\frac{L}{k}  = \frac{C"}{k} \\C" = L

A = \frac{L}{k}  - \frac{L}{k} e^{kt}

So, D = R - A =

D = \frac{L}{k} - \frac{L}{k}  - \frac{L}{k} e^{kt}\\D = \frac{L}{k} e^{kt}

when t = 0(at initial time), the initial value of D =

D = \frac{L}{k} e^{kt}\\D = \frac{L}{k} e^{k0}\\D = \frac{L}{k} e^{0}\\D = \frac{L}{k}

4 0
3 years ago
What is a number that is multiplied by variable?
patriot [66]

A term can be a signed number, a variable, or a constant multiplied by a variable or variables. Each term in an algebraic expression is separated by a + sign or J sign. ... When a term is made up of a constant multiplied by a variable or variables, that constant is called a coefficient.

4 0
3 years ago
Read 2 more answers
Admission to a baseball game is $3.00 for general admission and $5.50 for reserved seats. The receipts were $3277.50 for 845 pai
a_sh-v [17]

Answer:

548, 297

Step-by-step explanation:

We can set this up as a system of equations. The first equation is for how many tickets were sold, which is x+y=845. The second equation is for the cost of the tickets, which is 3x+5.5y=3277.50. The best method for this problem (other than graphing) is elimination. First, we need to multiply one equation to get the opposite of one of the variables. The easiest one to do for this problem is x. The opposite of 3 is -3, so we have to multiply ALL of the first equation by -3. If you do this, then you get -3x-3y=-2535. Now, combine the equations:

3x + 5.5y = 3277.50

-3x  -3y    = -2535

________________

0x+2.5y=742.5

Now, isolate y by dividing both sides by 2.5. If you do this, you get y=297. Now, plug this in for the y in the first equation. Isolate x.

x+297=845

  -297  -297

__________

      0      548

x=548

Hope this helps!

7 0
2 years ago
8th grade word problem... Can someone please help if you don’t know then please don’t answer...
QveST [7]

Answer:

30 of each type sold.

Step-by-step explanation:

It would be 30 since the LCM of 10 and 3 is 30.

If you need further explanation, reply to this answer but that's about it.

8 0
3 years ago
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