Answer:
The expected net winnings for the bet are -$1.0526
Step-by-step explanation:
P(x =+$20) = P(Black outcome) = 18/38
P(x =-$20) = P(red outcome) + P(green outcome)
= 18/38 + 2/38 = 20/38
Hence the probability distribution of x = $20 , P(x) = 18/38
x = -$20, P(x) = 20/38
Expected value of the random variable x is given by ;
miu = Summation [xP(x)] = 20(18/38) - 20( 20/38)
= -$1.0526
hence, the expected net winnings for the bet are -$1.0526
This implies that if a player bet on a very large number of games, the player would on the average lose $1.0526 per single bet
B -6 because absolute value ignores negatives
If the glasses hold two cups of liquid then you simply have to remember that there are 8 oz. in one cup.
so 8 times 2 = 16 oz. in two cups
The numbers decrease by 6.
-1, -8, -14, -20, -26, -32, -38, -44, -50, -56, -62, -68, -74, -80, -86, -92, -98, -104, -110, -116, -122, -128, -134, -140, -146
When I did the math I got 0.01 lbs
