Let the solutions be a and b.
a = -2; b = -10
a + b = -2 + (-10) = -12
ab = (-2)(-10) = 20
(x - a)(x - b) = 0
(x - (-2))(x - (-10)) = 0
(x + 2)(x + 10) = 0
x^2 + 10x + 2x + 20 = 0
x^2 + 12x + 20 = 0
-h = 12
h = -12
4k = 20
k = 5
Answer:
<h2>13</h2>
Step-by-step explanation:
6+
(4)(12)
/12
−2+5
=6+
48
/12
−2+5
=6+4−2+5
=10−2+5
=8+5
=13
Answer:
8
Step-by-step explanation:
I believe that the answer is 8
<span><span>The sum of a squared and b is given by

</span>7 times the sum of a squared and b is given by
</span><span>
while 4 times the sum of a squared and b is given by
</span>

Therefore, <span>7 times the sum of a squared and b minus 4 times the sum of a squared and b is given by

</span>