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3 years ago

What is the equation of a line parallel to y = x+2 and passes through (1, 2)?

Mathematics

1 answer:

kicyunya [14]3 years ago

7 0

Answer: y - x = 1

Step-by-step explanation: Note : for two lines to be parallel, then they have the same slope.

i.e the slope is 1

Using y - y1 = m ( x-x1) to find the equation of the line

⇒ y - 2 = 1 (x - 1)

y - 2 = x - 1

y - x = -1 +2

y - x = 1

it could also be written in slope intercept form as y = x + 1

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Please help!!!!!!!!!!

Delicious77 [7]

$f(x)=2x^2-4x+1$

Substitute the values of x to the equation of the function f:

$x=-1\to f(-1)=2(-1)^2-4(-1)+1=2(1)+4+1=7\\\\x=2\to f(2)=2(2^2)-4(2)+1=2(4)-8+1=1$

Therefore we have two points (-1, 7) and (2, 1).

We can calculate the slope of line l.

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

Substitute:

$m=\dfrac{1-7}{2-(-1)}=\dfrac{-6}{3}=-2$

<h3>Answer: A) -2.</h3>

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3 years ago

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tangare [24]

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3 years ago

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bagirrra123 [75]

Answer:

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Step-by-step explanation:

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Find the equation of the line passing through (-2,8) and (5,-3)

Advocard [28]

y = -2/3x + 5

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trapecia [35]

Answer:

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Step-by-step explanation:

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