Answer:
BRUH I DONT KNOW
Step-by-s
4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) DO ALL OF THAT TO FIND THE ANSWER
Answer:
perimeter = 6w
area = 2w^2
Step-by-step explanation:
we can use the variable w for width, and 2w for length perimeter would be width + width + length + length, or 6w
area is width x length or 2w^2
Answer:
2 5/8 - 6 1/4 + 8 1/2\
=
227
/8
Step-by-step explanation:
hope this helps :)
Let x be the speed.
Maximum is 65 so x needs to be less than or equal to 65.
The minimum is 45, so x also has to be greater than or equal to 45
45 <= x => 65
