Write the fraction of 12/15 in its simple form

2 answers:

7 0

Answer:

4/5

Explanation:

Find the Greatest Common Factor (GCF) of 12 and 15,If it exists, and by dividing both the numerator and denominator by it, reduce our fraction. GCF = 3, and our simplified answer

12 ÷ 3 = 4
15 ÷ 3 = 5

So the answer is 4/5

Ugo [173]3 years ago

4 0

Answer:

4/5

Step-by-step explanation:

To get the answer, find the GCF (greatest common factor) of the numerator and the denominator. Once you have the GCF, divide the 12 and 15 by that number. Here, the GCF is 3.

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grin007 [14]

By Green's theorem,

$\displaystyle\int_{x^2+y^2=9}\vec F(x,y)\cdot\mathrm d\vec r=\iint_D\left(\frac{\partial(xy)}{\partial x}-\frac{\partial(x^2)}{\partial y}\right)\,\mathrm dx\,\mathrm dy=\iint_Dy\,\mathrm dx\,\mathrm dy$

where $C$ is the circle $x^2+y^2=9$ and $D$ is the interior of $C$ , or the disk $x^2+y^2\le1$ .

Convert to polar coordinates, taking

$\begin{cases}x=r\cos\theta\\y=r\sin\theta\end{cases}\implies\mathrm dx\,\mathrm dy=r\,\mathrm dr\,\mathrm d\theta$

Then the work done by $\vec F$ on the particle is

$\displaystyle\iint_Dy\,\mathrm dx\,\mathrm dy=\int_0^{2\pi}\int_0^3(r\sin\theta)r\,\mathrm dr\,\mathrm d\theta=\left(\int_0^{2\pi}\sin\theta\,\mathrm d\theta\right)\left(\int_0^3r^2\,\mathrm dr\right)=\boxed0$