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IrinaK [193]
3 years ago
10

How do I had mixed numbers as a 5th grader

Mathematics
1 answer:
Fantom [35]3 years ago
4 0

Simple. 1.5 as a fraction is 1 & 1/2. If you know how to make fractions decimals, you're set.

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on Monday joe bought 10 cups of coffee and 5 doughnuts for his his office at the cost of $16.50. It turns out that the doughnuts
AfilCa [17]

X= be coffee

Y=be donuts


Set up equations


10x+5y=16.50

5x+10y=14.25


Now multiply first equation by -2 to get a negative


(-2)10x+5y(-2)=16.50(-2)


-20x-10y=-33


Now put both equations to solve for x


-20x-10y=-33

5x+10y=14.25

___________

-15x. = -18.75


Now divide -15 bith sides to get x alone


X= -18.75/-15


X= 1.25



The cost of each coffee cup$1.25



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3 years ago
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3 years ago
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7 times as much as the sum of 1/3 and 4/5
Jet001 [13]
First of all, you add 1/3 and 4/5, so you get:
\frac{1}{3} +  \frac{4}{5}

To add 2 fractions, they need to have the same denominator. Since 3 and 5 don't have a common factor, so you multiply 1/3 by 5, and 4/5 by 3, so you get:
\frac{1*5}{3*5} +  \frac{4*3}{5*3}
\frac{5}{15} +  \frac{12}{15}

Now, the two fractions got the same denominator, and you can add them by adding the numerators over the same denominator. (You don't add denominators in addition) so you get:
\frac{5+12}{15}
\frac{17}{15}

That's the sum of 1/3 + 4/5.

Now, they want the sum of the 2 fractions 7 times. So you multiply 17/15 by 7. And as you know, 7 = 7/1. So you get:
\frac{17}{15} *  \frac{7}{1}

In multiplication no need to have the same denominator. You multiply nominators by nominators and denominators by denominators. So you get:
\frac{17*7}{15*1}
\frac{119}{15}

Since 119 and 15 don't have a common factor, so they can't be simplified.
So, the answer is 119/15. 

Hope this Helps! :D
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3 years ago
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In a trivia game your team has -6 points. The other team has 15 points. What is the difference in points between the two teams
Alex

15 - -6 = 21. 21 points!

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3 years ago
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I have a geometry pre course test I need help
harkovskaia [24]

Answer:

What do you need help with, comment

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