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user100 [1]
3 years ago
6

5x+6y=13;-5x+2y=11. how do I solve this

Mathematics
1 answer:
Wittaler [7]3 years ago
8 0
You solve for X in one equation and plug it into the other. So... 

<span>5x+6Y=13 </span>
<span>5x=13-6Y </span>
<span>x=(13-6Y)/5 </span>

<span>Then, you replace X in the other equation... </span>

<span>-5x+2y=11 </span>
<span>-5[(13-6y)/5]+2y=11 </span>
<span>-13+6y+2y=11 </span>
<span>8y=11+13 </span>
<span>8y=24 </span>
<span>y=3 </span>

<span>Now that you have Y, you just solve for x using either equations... </span>

<span>5x+6(3)=13 </span>
<span>5x=13-18 </span>
<span>5x=-5 </span>
<span>x=-1 </span>

<span>Therefore, X = -1 & Y = 3

</span>
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Answer:

slope of the first line: 1

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slope of the third line: 0.375

slope of the fourth line: 1.25

Step-by-step explanation:

Given two points (x1, y1) and (x2, y2), the slope of a line is computed as follows:

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slope of the first line: [5 - (-4)]/[4 - (-5)] = 1

slope of the second line: [5 - (-2)]/[4 - (-5)] = 0.778

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slope of the fourth line: [5 - (-5)]/[4 - (-4)] = 1.25

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